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2 years ago

Can someone please solve this and save my life

Mathematics

1 answer:

dexar [7]2 years ago

7 0

Answer:

As follows,

Step-by-step explanation:

Find the attachment.

Distance of PQ=√13

Distance of QR=√13

Distance of PR=√26

Thus, PQR is an isosceles triangle.

Distance of MN=√(16+(a-2)^2)

16=16+a^2-4a+4

a^2-4a+4=0

a=2

Distance of RS=√(9+(b+1)^2)

25=9+b^2+2b+1

b=3 or -5

Distance of RS=√(9+(-1-c)^2)

18=9+c^2 + 2 c + 1

c=-4,2

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Answer:

AC=32 units.

Step by step explanation:

Given information: B, D, and F are midpoints if the sides of ΔACE, EC = 38 and DF = 16.

Consider the below figure attached with this question.

According to the midpoint theorem, if a line segments connecting two midpoints then the line is parallel to the third side and it's length is half of the third side.

Since F and D are midpoints of AE and EC respectively.

Using midpoint theorem, the length of AC is twice of DF.

$AC=2\times DF$

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