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3 years ago

Dakota has 4/10 kg of clay he divided the clay to make eight equal parts how many grams of clay are in each pot

Mathematics

1 answer:

Gwar [14]3 years ago

4 0

Answer:

Dakota must put 50 grams of clay in each pot to be able to divide the clay into 8 equal parts.

Step-by-step explanation:

Given that Dakota has 4/10 kg of clay and I divided the clay to make eight equal pots, to determine how many grams of clay are in each pot the following calculation must be performed:

4/10 kg = 0.4 kg = 400 grams

400/8 = X

50 = X

Thus, Dakota must put 50 grams of clay in each pot to be able to divide the clay into 8 equal parts.

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A, B, and C are collinear B is between A and C.

mixas84 [53]

Answer:

x = 7

Step-by-step explanation:

A, B, and C are collinear B is between A and C.

AC = AB + BC

2x + 1 = x + 4 + 2x - 10

2x + 1 = 3x - 6

2x - 3x = - 6 - 1

- x = - 7

x = 7

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3 years ago

MATH HELP ASAP!! MARKING BRAINLIEST

olga nikolaevna [1]

Answer:

-1, -7, -13, -19

Step-by-step explanation:

-2(-3)-7 =6-7= -1

-2(0)-7 =0-7= -7

-2(3)-7 =-6-7= -13

-2(6)-7 =-12-7= -19

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3 years ago

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Find the volumes of the solids generated by revolving the triangle with vertices (2, 2), (2, 6), and (5, 6) about a) the x-a

Vesna [10]

About the $x$ -axis (washer method):

$\displaystyle\pi\int_2^5\left(6^2-\left(\frac43x-\frac23\right)^2\right)\,\mathrm dx=\frac{16\pi}9\int_2^5(20+x-x^2)\,\mathrm dx=\boxed{56\pi}$

About the $y$ -axis (shell method):

$\displaystyle2\pi\int_2^5x\left(6-\left(\frac43x-\frac23\right)\right)\,\mathrm dx=\frac{8\pi}3\int_2^5x(5-x)\,\mathrm dx=\boxed{36\pi}$

About $x=7$ (shell method):

$\displaystyle2\pi\int_2^5(7-x)\left(6-\left(\frac43x-\frac23\right)\right)\,\mathrm dx=\frac{8\pi}3\int_2^5(35-12x+x^2)\,\mathrm dx=\boxed{48\pi}$

About $y=2$ (washer method):

$\displaystyle\pi\int_2^5\left((6-2)^2-\left(\frac43x-\frac23-2\right)^2\right)\,\mathrm dx=\frac{16\pi}9\int_2^5(5+4x-x^2)\,\mathrm dx=\boxed{32\pi}$

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4 years ago

8x2 − 5 + 7x4 − 9x − x5

Veseljchak [2.6K]

Answer:

$=-\left(x-1\right)\left(x^4-6x^3-6x^2-14x-5\right)$

Step-by-step explanation:

Factor out comon Term -1

$=-\left(x^5-7x^4-8x^2+9x+5\right)$

Factor $x^5-7x^4-8x^2+9x+5:\quad \left(x-1\right)\left(x^4-6x^3-6x^2-14x-5\right)$

$x^5-7x^4-8x^2+9x+5$

Use the rational root theorem

$a_0=5,\:\quad a_n=1$

The dividers of $a_{0}$ : 1, 5, The dividers of $a_n$ : 1

Therefore, check the following rational numbers: ± $\frac{1,\:5}{1}$

$\frac{1}{1}$ is a root of the expression, so factor out $x-1$

$=\left(x-1\right)\frac{x^5-7x^4-8x^2+9x+5}{x-1}$

$\frac{x^5-7x^4-8x^2+9x+5}{x-1}=x^4-6x^3-6x^2-14x-5$

$=x^4-6x^3-6x^2-14x-5$

$=-\left(x-1\right)\left(x^4-6x^3-6x^2-14x-5\right)$

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3 years ago

the ratio of the weight of an object on earth to the weight of the same object on pluto is 100 to 3. if and elephants weighs 410

Over [174]

You mean find the elephant's weight on Pluto?

100:3 & 4100:x

4100/100 = 41
3*41 = 123

The ratio would become 4100:123 with the elephant's weight on Pluto as 123 pounds.

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3 years ago

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