To solve this problem, let us first assign some
variables. Let us say that:
x = pigs
y = chickens
z = ducks
From the problem statement, we can formulate the
following equations:
1. y + z = 30 --->
only chicken and ducks have feathers
2. 4 x + 2 y + 2 z = 120 --->
pig has 4 feet, while chicken and duck has 2 each
3. 2 x + 2 y + 2 z = 90 --->
each animal has 2 eyes only
Rewriting equation 1 in terms of y:
y = 30 – z
Plugging this in equation 2:
4 x + 2 (30 – z) + 2 z = 120
4 x + 60 – 2z + 2z = 120
4 x = 120 – 60
4 x = 60
x = 15
From the given choices, only one choice has 15 pigs. Therefore
the answers are:
She has 15 pigs, 12 chickens, and 18 ducks.
Im not sure but CBA i think it has to do with some bank
The Answer is B Step-by-step explanation: it's the 2.3 with a line above the 3
<span>y-3=-2(x-6)
y-3= -2x +12
y - 3 + 2x- 12 =0
2x+y =15,
Ax +By =C
A=2, B=1, C=15</span>
X+y=10 in y-intercept is y=-x+10. 10 is the y intercept. The ordered pair is (0, 10)
