8.652 10) 1.2 Help please
2 answers:
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Answer:
720 ways
Step-by-step explanation:
Generally, combination is expressed as;
The question consists of 9 multiple-choice questions and examinee must answer 7 of the multiple-choice questions.
⇒ ⁹C₇
= 36
The question consists of 6 open-ended problems and examinee must answer 3 of the open-ended problems.
⇒ ⁶C₃
= 20
Combining the two combinations to determine the number of ways the questions and problems be chosen if an examinee must answer 7 of the multiple-choice questions and 3 of the open-ended problem.
⁹C₇ × ⁶C₃
= 36 × 20
= 720 ways