Vertex form of an equation for a parabola looks like this:
f(x) = a(x-h)² + k
(h,k) is the vertex. Just plug in the values (3,-2)
f(x) = a(x-3)² - 2
Now use the point (5,-1) to find "a" so that the equation goes through that point.
-1 = a(5-3)² - 2
-1 = a(2)² - 2
-1 = 4a - 2
-1 + 2 = 4a
1 = 4a
1/4 = a
put that into the equation to get the answer
f(x) = (1/4)(x - 3)² - 2
Answer:
it is so hard men and there is no solution maybe you can search on siri
Its B bro becauseiys a negative so you would get rid of the symbol then flip the negative
Answer: s^2-5s-1/s
Step-by-step explanation: Simplify the expression.
Hope this helps you out! ☺
Answer:
see below
Step-by-step explanation:
domain is all x values for which a graph has
and range is all y values for which a graph has
domain in this case is -4<x<4. The range is -3<= x <= 3
Function is increasing when slope of the line is positive, function is decreasing when slope of the line is negative.
When 2 lines meet and there is an edge like at (-1,3) there is no increase of decrease of the function. If you are in calculus, this is because the derivative of the function will not be valid at those points. If you are not in calculus, then don't pay attention to the derivative stuff.
Function is increasing on interval -4<x<-1 and 2<x<4
Function is decreasing on interval -1<x<2