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2 years ago

In a standard deck of 52 cards what is the probability of drawing 2 jacks

Mathematics

1 answer:

rusak2 [61]2 years ago

7 0

Answer:

1/169

Step-by-step explanation:

There are 4 jacks in a deck of cards.

So 4/52 is the probability of drawing 1 card

The probability of drawing 2 jacks is 4/52*4/52

Solve, and that is 1/169

I hope this helps!

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Can I get some help, it is due in 15 minutes and I need help. Thanks, any help appreciated

koban [17]

Well, I'm way past the 15 min mark, but here's how to do the question.

With this, you will need to use the distance formula, $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ , on XY, YZ, and ZX.

XY: $\sqrt{(3-1)^2+(1-6)^2}$

Firstly, solve inside the parentheses: $\sqrt{(2)^2+(-5)^2}$

Next, solve the exponents: $\sqrt{4+25}$

Next, solve the addition, and XY's distance will be √29

(The process is the same with the other 2 sides, so I'll go through them real quickly)

YZ:

$\sqrt{(6-3)^2+(3-1)^2}\\ \sqrt{(3)^2+(2)^2}\\ \sqrt{9+4}\\ \sqrt{13}$

ZX:

$\sqrt{(1-6)^2+(6-3)^2}\\ \sqrt{(-5)^2+(3)^2}\\ \sqrt{25+9}\\ \sqrt{34}$

Now that we got the 3 sides, we can add them up: $\sqrt{29}+\sqrt{13} +\sqrt{34} =14.8$

In short, your answer is 14.8, or the second option.

8 0

2 years ago

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kolbaska11 [484]

Answer:

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2 years ago

2/9 of the people on the restaurant are adults. If there are 95 more children than adults, how many children are there in the re

yan [13]

A: Adults
C:children
P: people
A= 2/9 P
C= A+95
P= A+C
= 2/9P + 2/9P+95
= 4/9 P+95, add -4/9P for both sides (same terms, same sides:))
P- 4/9P= 95
5/9P= 95
P= 171 people in the restaurant
Adult= 2/9*171= 38 Adults
Children= 38+95= 133 children

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2 years ago

Find y if x=15 if y is 6 x=30

Len [333]

I'm not sure if this question was correctly transcribed but is it suppose to read find if x=15, find y = 6x+30 ?

If so then y = 120

The way it is written now, If x = 15 then 6x cannot equal 30 which is why I asked. Sorry if I'm not understanding the question.

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2 years ago

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2 years ago