Ummm hmm this is a hard one..... I believe it’s 88?
The given triangle is a right triangle.
The tangent of an angle of right triangle is obtained by dividing the opposite side of the angle with the adjacent side of the angle.
The opposite side of angle R is 5 cm and the adjacent side of angle R is 12 cm.
tan R = 5 / 12 = 0.4167
R = arctan (0.4167) = 22.6 degrees.
-2m+4m+5=3
(-2m+4m)+(5)=3
2m+5=3
2m+5-5=3-5
2m=-2
2m/2=-2/2
m=-1
Answer:
1 / We have the area of a rectangle ABCD = 8 x 16 = 128 ft²
2 / Find the area of an isosceles Δ DEF:
The base of the isosceles ΔDEF => DF = DC- FC = 16 -12 = 4 ft
So the area of Δ DEF = 1/2 (DF x EH) = 1/2 (4 x 6) = 12 ft²
3 / Area of the irregular shape = area ABCB + Area DEF = 128 + 12 = 140 ft²
Step-by-step explanation:
What are we exactly supposed to solve for here
