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3 years ago

HELP HELP HELP PLS pls lol

Mathematics

1 answer:

labwork [276]3 years ago

5 0

Answer:

Step-by-step explanation:

because the x value -4 has two y values.

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Expand and combine like terms. (4b^2+ 3) (4b^2- 3) = 1 SEE ANSWER

krok68 [10]

Answer:

Step-by-step explanation:

(4b^2+3)(4b^2-3)

since it is the expanded form of formula a^2-b^2=(a+b)(a-b) we can write,

=(4b^2)^2-(3)^3

=16b^4-9

8 0

3 years ago

What is the answer to this math problem 4-3= 8-9=

ivann1987 [24]

Answer:

4-3=1

8-9=-1

Step-by-step explanation:

I hope this helps

3 0

3 years ago

Caculate and show answer

kipiarov [429]

(3 1/2+8 2/3)-3 5/6
= 1.898717
(10 1/4 - 5 5/8)-1 3/8
= -5.221721

(2 2/3+ 4 5/6)+3 3/8
= 9.795734

3 0

4 years ago

An acute triangle has sides measuring 10 cm and 16 cm. The length of the third side is unknown.

saveliy_v [14]

Answer: Choice B

12.5 < x < 18.9

================================================

Explanation:

We have a triangle with these side lengths:

a = 10
b = 16
c = x = unknown

Let's assume that b = 16 is the largest side of this triangle.

By the converse of the pythagorean theorem, we need $b^2 < a^2+c^2$ to be true in order for an acute triangle to happen.

So,

$b^2 < a^2 + c^2\\\\c^2 > b^2 - a^2\\\\c > \sqrt{b^2-a^2}\\\\x > \sqrt{16^2-10^2}\\\\x > \sqrt{156}\\\\x > 12.4899959967968 \ \text{(approximate)}\\\\x > 12.5$

Now let's consider the possibility that the missing side x is actually the longest side.

Using the same theorem as before, we would say,

$c^2 < a^2 + b^2\\\\c < \sqrt{a^2 + b^2}\\\\x < \sqrt{10^2 + 16^2}\\\\x < \sqrt{356}\\\\x < 18.8679622641132 \ \text{(approximate)}\\\\x < 18.9\\\\$

We found that x > 12.5 and x < 18.9

This is the same as saying 12.5 < x and x < 18.9

Put together, they form the approximate answer of 12.5 < x < 18.9

6 0

3 years ago

4)Without a calculator, name the zeros and sketch the graph. 56.) = -2x(x-4)^2(x+3)^2

Ilia_Sergeevich [38]

Answer:

0, 4, -3

Step-by-step explanation:

replace y with 0 and then fro the sketch I recommend you tomuse desmos good luck buddie

6 0

3 years ago