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matrenka [14]
3 years ago
6

The value of 3 in 46.132 is how many times the value of the 3 in 8.553A 10B 1 C 1/10

Mathematics
1 answer:
kifflom [539]3 years ago
4 0

Answer:

The value of 3 in 46.132 is 10 times the value of 3 in 8.553.

Step-by-step explanation:

The value of 3 in 46.132 is in hundredth's place.

The value of 3 in 8.553 is in thousandths place.

We can write as :

For 46.132, its value is \dfrac{3}{100} and for 8.553 its value is \dfrac{3}{1000}.

Taking,

\dfrac{\dfrac{3}{100}}{\dfrac{3}{1000}}=10

So, the value of 3 in 46.132 is 10 times the value of 3 in 8.553. Hence, the correct answer is A.

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Answer:

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Step-by-step explanation:

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fenix001 [56]
Answers


Explanation

So first we’re gonna change the equation to y=Mx+b by subtracting the 8x and then dividing both sides by -4. This can be show like this

8x-4y=12
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Evaluate (x + y)0 for x = -3 and y = 5.<br><br> A. -1/2<br> B. 0<br> C. 1<br> D. 2
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1. The mechanics at Lincoln Automotive are reborning a 6 in deep cylinder to fit a new piston. The machine they are using increa
Firdavs [7]

Answer:

0.0239\frac{in^{3}}{min}

Step-by-step explanation:

In order to solve this problem, we must start by drawing a diagram of the cylinder. (See attached picture)

This diagram will help us visualize the problem better.

So we start by determining what data we already know:

Height=6in

Diameter=3.8in

Radius = 1.9 in (because the radius is half the length of the diameter)

The problem also states that the radius will increase on thousandth of an inch every 3 minutes. We can find the velocity at which the radius is increasing with this data:

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which yields:

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with this information we can start solving the problem.

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V=\pi r^{2}(6)

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We can now take the derivative to this formula so we get:

\frac{dV}{dt}=2(6)\pi r \frac{dr}{dt}

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We can now substitute the data provided by the problem to get:

\frac{dV}{dt}=12\pi (1.9) (\frac{1}{3000})

which yields:

\frac{dV}{dt}=0.0239\frac{in^{3}}{min}

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