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3 years ago

6. Find the area of each figure, round your answer to

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

5 0

Answer:

Here you go

Step-by-step explanation:

A. 4070

B. 310

c. 410

D. 307.0

120 cm

10 cm

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IF YOU CLICK ME YOU HELP ME =)

Doss [256]

The median is the number that is in the middle of all the other numbers in order but that is not the case
however, it is not the mean either
so we can see that 9.25 is between 9 and 9.5 when 23.5 is ignored
the correct answer is B

8 0

3 years ago

Complete a b and c if you do one it would mean alot

victus00 [196]

Answer: I don't see what your talking about here, so I can't help you.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Teri went shopping with $300. Her Christmas shopping list is: 5 barbies for $10.50 each,, earbuds for $45, 3 sweaters for $22 ea

Romashka [77]

5 times 10.50 = $52.5

An additional $45

3 times 22 = $66

An other additional $65

The total price her shopping list costs is 229.5

Now, $300 - $229.5 = $70.5

Teri will have $70.50 left after buying these items.

3 0

3 years ago

What is thr inverse of f(x) if the function is x=-4,-2,0,2,4 f(x)=-2,-1,0,1,2

Lorico [155]

For a function, if it has an inverse function, keep in mind that, the "domain of the original, is the range of the inverse, and the range of the original, is the domain of the inverse", what the dickens does that mean?

well, it means the values for "x" and f(x), on the inverse, are the same values, but swapped up, therefore

$\bf \stackrel{original~function}{\begin{array}{ccll}
x&f(x)\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
-4&-2\\
-2&-1\\
0&0\\
2&1\\
4&2
\end{array}}\qquad \qquad \qquad 
\stackrel{inverse~function}{\begin{array}{ccll}
x&f(x)\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
-2&-4\\
-1&-2\\
0&0\\
1&2\\
2&4
\end{array}}$

7 0

3 years ago

The components of vector A are (10.5, 10.2). Waht is the magnitude of the vector?

Nataly_w [17]

Answer:

$||\overrightarrow{v}||\approx14.64$

Step-by-step explanation:

The magnitude of a vector $\displaystyle \overrightarrow{v}=\langle x,y\rangle$ is $||\overrightarrow{v}||=\sqrt{x^2+y^2}$ , which essentially describes the length of the vector itself between the initial and terminal points:

$||\overrightarrow{v}||=\sqrt{x^2+y^2}\\\\||\overrightarrow{v}||=\sqrt{(10.5)^2+(10.2)^2}\\\\||\overrightarrow{v}||=\sqrt{110.25+104.04}\\\\||\overrightarrow{v}||=\sqrt{214.29}\\\\||\overrightarrow{v}||\approx14.64$

6 0

2 years ago