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s344n2d4d5 [400]
3 years ago
9

Find all possible values of k so that x^2 + kx - 32 can be factored.

Mathematics
1 answer:
daser333 [38]3 years ago
8 0

Answer:

Step-by-step explanation:

The posssible factors are

x^2 + 4x - 32

(x+8)(x-4)

x^2+ 14x - 32

(x+16)(x-2)

(x+32)(x-1)

x^2+31x-32

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6. In right triangle ABC, mZC=3y-10,
lorasvet [3.4K]

Answer:

scalene

Step-by-step explanation:

step 1

Find the value of y

we know that

The sum of the interior angles in a triangle must be equal to 180 degrees

In this problem

m∠A+m∠B+m∠C=180°

substitute the given values

90\°+(y+40)\°+(3y-10)\°=180\°

Solve for y

4y+120=180

4y=180-120

4y=60

y=15

step 2

<em>Find the measure of angle B</em>

m∠B=(y+40)°

substitute the value of y

m∠B=(15+40)=55°

step 3

<em>Find the measure of angle C</em>

m∠C=(3y-10)°

substitute the value of y

m∠C=(3(15)-10)=35°

The three interior angles are different

so

The three sides of the ABC triangle will also be different

therefore

The right triangle ABC is scalene

6 0
3 years ago
the perimeter of the quadrilateral is 49 centimeters. find the length of each side. x+9 , x^2-2x , x+4 , 3x-4
shtirl [24]
X= 5 or -8

Add all the like terms and set it equal to 49, use quadratic formula or factoring. 
3 0
3 years ago
I don't know how to solve it.
Nataly [62]

Step-by-step explanation:

Take the first derivative

\frac{d}{dx} ( {x}^{3}  - 3x)

3 {x}^{2}  - 3

Set the derivative equal to 0.

3 {x}^{2}  - 3 = 0

3 {x}^{2}  = 3

{x}^{2}  = 1

x = 1

or

x =  - 1

For any number less than -1, the derivative function will have a Positve number thus a Positve slope for f(x).

For any number, between -1 and 1, the derivative slope will have a negative , thus a negative slope.

Since we are going to Positve to negative slope, we have a local max at x=-1

Plug in -1 for x into the original function

( - 1) {}^{3}  - 3(  - 1) = 2

So the local max is 2 and occurs at x=-1,

For any number greater than 1, we have a Positve number for the derivative function we have a Positve slope.

Since we are going to decreasing to increasing, we have minimum at x=1,

Plug in 1 for x into original function

{1}^{3}   - 3(1)

1 - 3 =  - 2

So the local min occurs at -2, at x=1

8 0
2 years ago
In the equation f(x) = 5x + 6,6 is called?
Vikentia [17]

Answer:

the y-intercept

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=-24%5Cleq%203x-9" id="TexFormula1" title="-24\leq 3x-9" alt="-24\leq 3x-9" align="absmiddle" c
dybincka [34]

If your solving for x, you need to isolate/get the variable "x" by itself in the inequality:

-24 ≤ 3x - 9        First add 9 on both sides

-24 + 9 ≤ 3x - 9 + 9

-15 ≤ 3x        Then divide 3 on both sides to get "x" by itself

\frac{-15}{3} \leq \frac{3x}{3}

-5 ≤ x                  [or  x ≥ -5 if you prefer "x" to be on the left side]

8 0
3 years ago
Read 2 more answers
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