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Thepotemich [5.8K]
3 years ago
12

Whats ten ximes eight?

Mathematics
1 answer:
mart [117]3 years ago
6 0

Answer:

80

Step-by-step explanation:

you have 8 ten times add 8 together ten times you get 80

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A retangular athletic field is twice as long as it is wide. If the perimeter of the athletic field is 180 yards, what are its di
pishuonlain [190]
W= width
l= 2w= length

Perimeter of a Rectangle Formula
P= 2(l + w)
substitute 2w for l in equation

180= 2(2w + w)
multiply 2 by parentheses

180= 4w + 2w
combine like terms

180= 6w
divide both sides by 6

30 yards= w


LENGTH
2w= 2(30)= 60 yards

CHECK:
180= 30 + 60 + 30 + 60
180= 90 + 90
180= 180


ANSWER: the width is 30 yards and the length is 60 yards

Hope this helps! :)
5 0
3 years ago
3x^2-5x-24<br> identify p and q
Novay_Z [31]
3x^2-5x-24=0

3x^2-5x=24

x^2-5x/3=8

x^2-5x/3+25/36=8+25/36

(x-5/6)^2=313/36

x-5/6=±√(313/36)

x=5/6±√(313/36)

x=(5±√313)/6

p=(5+√313)/6

q=(5-√313)/6
4 0
3 years ago
When u are doing math and u have a question with pi in it don't u use "3.14" or do u use "3.141" or is it "3.14159?
Tju [1.3M]
Usually, I use 3.14.
7 0
4 years ago
Read 2 more answers
The difference between the highest and lowest score in a distribution
trasher [3.6K]

Answer:

Range

Step-by-step explanation:

In statistics, the range of a set of data is the difference between the largest and smallest value in the distribution. It is calculated by subtracting the lowest value from the highest value. The range shows how widely spread out a set of given data is.

4 0
3 years ago
Find the distance between a point (– 2, 3 – 4) and its image on the plane x+y+z=3 measured across a line (x + 2)/3 = (2y + 3)/4
dimaraw [331]

Answer:

Distance of the point from its image = 8.56 units

Step-by-step explanation:

Given,

Co-ordinates of point is (-2, 3,-4)

Let's say

x_1\ =\ -2

y_1\ =\ 3

z_1\ =\ -4

Distance is measure across the line

\dfrac{x+2}{3}\ =\ \dfrac{2y+3}{4}\ =\ \dfrac{3z+4}{5}

So, we can write

\dfrac{x-x_1+2}{3}\ =\ \dfrac{2(y-y_1)+3}{4}\ =\ \dfrac{3(z-z_1)+4}{5}\ =\ k

=>\ \dfrac{x-(-2)+2}{3}\ =\ \dfrac{2(y-3)+3}{4}\ =\ \dfrac{3(z-(-4))+4}{5}\ =\ k

=>\ \dfrac{x+4}{3}\ =\ \dfrac{2y-3}{4}\ =\ \dfrac{3z+16}{5}\ =\ k

=>\ x\ =\ 3k-4,\ y\ =\ \dfrac{4k+3}{2},\ z\ =\ \dfrac{5k-16}{3}

Since, the equation of plane is given by

x+y+z=3

The point which intersect the point will satisfy the equation of plane.

So, we can write

3k-4+\dfrac{4k+3}{2}+\dfrac{5k-16}{3}\ =\ 3

=>6(3k-4)+3(4k+3)+2(5k-16)\ =\ 18

=>18k-24+12k+9+10k-32\ =\ 18

=>\ k\ =\dfrac{13}{8}

So,

x\ =\ 3k-4

   =\ 3\times \dfrac{13}{8}-4

   =\ \dfrac{7}{4}

y\ =\ \dfrac{4k+3}{2}

   =\ \dfrac{4\times \dfrac{13}{8}+3}{2}

   =\ \dfrac{19}{4}

z\ =\ \dfrac{5k-16}{3}

  =\ \dfrac{5\times \dfrac{13}{8}-16}{3}

   =\ \dfrac{-21}{8}

Now, the distance of point from the plane is given by,

d\ =\ \sqrt{(x-x_1)^2+(y-y_1)^2+(z-z_1)^2}

   =\ \sqrt{(-2-\dfrac{7}{4})^2+(3-\dfrac{19}{4})^2+(-4+\dfrac{21}{8})^2}

   =\ \sqrt{(\dfrac{-15}{4})^2+(\dfrac{-7}{4})^2+(\dfrac{9}{8})^2}

   =\ \sqrt{\dfrac{225}{16}+\dfrac{49}{16}+\dfrac{81}{64}}

   =\ \sqrt{\dfrac{1177}{64}}

   =\ 4.28

So, the distance of the point from its image can be given by,

D = 2d = 2 x 4.28

            = 8.56 unit

So, the distance of a point from it's image is 8.56 units.

4 0
4 years ago
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