Answer:
<h2>He will use flowers per vase</h2><h2>but will have one left</h2>Step-by-step explanation:
In this problem we are required to place flowers evenly across 3 flower vases.
Given that we have 25 flower to collect from and distribute evenly.
we are going to divide 25 by 3
We have
<u><em>From the result in the improper fraction we can see the Darren can place 8 flowers evenly of the 25 flowers and there will be just one left over</em></u>
If <em>a</em> is the first term of an AP with common difference -2, then the first several terms are
<em>a</em>, <em>a</em> - 2, <em>a</em> - 4, <em>a</em> - 6, <em>a</em> - 8, …
with <em>n</em>-th term <em>a</em> - 2 (<em>n</em> - 1).
The sum of the first <em>n</em> terms is equal to the sum of the first 3<em>n</em> terms :
We have
so that in the previous equation, the sums reduce to
Solve for <em>a</em> :
Now if <em>a</em> = 27, we have
27 = 4<em>n</em> - 1
28 = 4<em>n</em>
<em>n</em> = 7
as required.