The missing number is the square-root of the constant term on the left-hand-side, which equals sqrt(1/16)=1/sqrt(16)=1/4.
Check:
(x+1/4)^2=x^2+2*(1/4)x+(1/4)^2=x^2+x/2+1/16. ok
Answer: x= 1/4
Answer:
y"(2, 1) = -5
Step-by-step explanation:
Step 1: Define implicit differentiation
5 - y² = x²
Step 2: Find dy/dx
- Take implicit differentiation: -2yy' = 2x
- Isolate y': y' = 2x/-2y
- Isolate y': y' = -x/y
Step 3: Find d²y/dx²
- Quotient Rule: y'' = [y(-1) - y'(-x)] / y²
- Substitute y': y" = [-y - (-x/y)(-x)] / y²
- Simplify: y" = [-y - x²/y] / y²
- Multiply top/bottom by y: y" = (-y² - x²) / y³
- Factor negative: y" = -(y² + x²) / y³
Step 4: Substitute and Evaluate
y"(2, 1) = -(1² + 2²) / 1³
y"(2, 1) = -(1 + 4) / 1
y"(2, 1) = -5/1
y"(2, 1) = -5
Area is square units, so the new area would be the scale factor squared:
Scale factor is 2, so the area would increase by 2^2 = 4
The answer is B.4
Answer:
Step-by-step explanation:
Curvilinear relationship
A curvilinear relationship is a type of relationship in which there are two variables. As and when the value of one variable increases, so does the value of the other. This continues until a certain point, after which an increase in one variable decreases the value of the other.
Example:
The two variables are - Work pressure and work performance. As work pressure increases, work performance increases until a certain point. After a threshold, when work pressure exceeds, work performance drops. This results in a curvilinear relationship between the two variables.
