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3 years ago

Need help ASAP plz and I've got more if anyone wants to help

Mathematics

1 answer:

rodikova [14]3 years ago

6 0

Answer:

1/4+1/4+1/4+1/4+1/4+1/4= 1.5

3/10x2/3= 0.2

2/4x2/3= 0.33333333333 (just put 0.3 with a line on top of the 3)

6 divided by 1/2 = 12/1 or 12

9 divided by 1/3 = 27/1 or 27

2/5 divided by 3/4 = 8/15

1/2 divided by 2/3 = 3/4

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The vertex form of h(x) = x2 – 14x + 6 is h(x) = (x – )2 – .

EastWind [94]

The vertex form of h(x) = x2 – 14x + 6 is h(x) = (x –7 )2 – 43.

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3 years ago

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How much water is in the cylinder ?

Mariulka [41]

Answer:

339π in³

Step-by-step explanation:

The amount of water is the difference between the volume of the cylinder and the volume of the ball. The appropriate volume formulas are ...

cylinder V = πr²h

sphere V = (4/3)πr³

For the given numbers, the volumes are ...

cylinder V = π(5 in)²(15 in) = 375π in³

sphere V = (4/3)π(3 in)³ = 36π in³

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water volume = cylinder V - sphere V

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5 0

3 years ago

(52) Pleaase check ym answer

Alinara [238K]

X = measure of each of the legs
"perimeter is 8 more than 2 times one of the legs" ---> P = 2x+8
P = 28 is the given perimeter

So,
P = 2x+8
28 = 2x+8
2x+8 = 28
2x = 20
x = 10

If x = 10, then the two legs add up to x+x = 10+10 = 20
Leaving P-20 = 28-20 = 8 inches left over for the base

You have the correct answer (choice D, 8 inches) though your steps are a bit confusing at some parts. Such as the part where you wrote 2x = 10 twice. I think I know what you were trying to say.

4 0

3 years ago

Solve for a. c = 8 π a b a. 8 π b c = a b. c/8π =a c. c/8πb =a d. c/8 =a

NNADVOKAT [17]

C = 8πab
a = c/8πb ..

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3 years ago

(a) A lamp has two bulbs of a type with an average lifetime of 1600 hours. Assuming that we can model the probability of failure

lara [203]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability is $P_T= 0.4560$

The probability is $P_F= 0.0013$

Step-by-step explanation:

From the question we are told that

The mean for the exponential density function of bulbs failure is $\mu = 1600 \ hours$

Generally the cumulative distribution for exponential distribution is mathematically represented as

$1 - e^{- \lambda x}$

The objective is to obtain the p=probability of the bulbs failure within 1800 hours

So for the first bulb the probability will be

$P_1(x < 1800)$

And for the second bulb the probability will be

$P_2 (x< 1800)$

So from our probability that we are to determine the area to the left of 1800 on the distribution curve

Now the rate parameter $\lambda$ is mathematically represented as

$\lambda$ $= \frac{1}{\mu}$

$\lambda = \frac{1}{1600}$

The probability of the first bulb failing with 1800 hours is mathematically evaluated as

$P_1(x < 1800) = 1 - e^{\frac{1}{1600} * 1800 }$

$= 0.6753$

Now the probability of both bulbs failing would be

$P_T=P_1(x < 1800) * P_2(x < 1800)$

$= 0.6375 * 06375$

$P_T= 0.4560$

Let assume that one bulb failed at time $T_a$ and the second bulb failed at time $T_b$ then

$T_a + T_b = 1800\ hours$

The mathematical expression to obtain the probability that the first bulb failed within between zero and $T_a$ and the second bulb failed between $T_a \ and \ 1800$ is represented as

$P_F=\int_{0}^{1800}\int_{0}^{1800-x} \f{\lambda }^{2}e^{-\lambda x}* e^{-\lambda y}dx dy$

$=\int_{0}^{1800} {\lambda }e^{-\lambda x}\int_{0}^{1800-x} {\lambda } e^{-\lambda y}dx dy$

$=\int_{0}^{1800} {\frac{1}{1600} }e^{-\lambda x}\int_{0}^{1800-x} \frac{1}{1600 } e^{-\lambda y}dx dy$

$=\int_{0}^{1800} {\frac{1}{1600} }e^{-\lambda x}[e^{- \lambda y}]\left {1800-x} \atop {0}} \right. dx$

$=\int_{0}^{1800} {\frac{1}{1600} }e^{-\frac{x}{1600} }[e^{- \frac{1800 -x}{1600} }-1] dx$

$=[ {\frac{1}{1600} }e^{-\frac{1800}{1600} }-\frac{1}{1600}[e^{- \frac{x}{1600} }] \left {1800} \atop {0}} \right.$

$=[ {\frac{1}{1600} }e^{-\frac{1800}{1600} }-\frac{1}{1600}[e^{- \frac{1800}{1600} }] -[[ {\frac{1}{1600} }e^{-\frac{1800}{1600} }-\frac{1}{1600}[e^{-0}]$

$=[\frac{1}{1600} e^{-\frac{1800}{1600} } - \frac{1}{1600} e^{-0} ]$

$=0.001925 -0.000625$

$P_F= 0.0013$

4 0

3 years ago

Read 2 more answers

Need help ASAP plz and I've got more if anyone wants to help​

Need help ASAP plz and I've got more if anyone wants to help