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ivolga24 [154]
4 years ago
11

2x+3y=23 3x-y=7 Solve for x

Mathematics
1 answer:
NeTakaya4 years ago
5 0
2x + 3y = 23...........................(1)

3x  - y  =  7   Multiply by 3:-

9x - 3y = 21      Adding this to equation (1):-

11x = 44
x = 

Plug this into equation (1):-
2(4) + 3y = 23

3y = 15
y = 5

Answer is x = 4, y = 5

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Lim t^4 - 6 / 2t^2 - 3t + 7
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I think you meant to say

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(as opposed to <em>x</em> approaching 2)

Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}

Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}

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Sphinxa [80]
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7 0
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Answer:

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Your answer would be

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7 0
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Read 2 more answers
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vekshin1

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