Can I do 50 quizzes in 2 weeks? Each takes about 5 minutes

2 answers:

8 0

So.
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Let's get started with formulas.
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I KNOW you hate formulas!! So do I, but we have to use them. No "buts".
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So, how many minutes are in 2 weeks?
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Search it up. For your convenience, it is 20,160 minutes.
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Well, I think you have your answer, since each quiz is 5 minutes, 5 times 50 (5 x 50) is 2,500 minutes.
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Yes, you can do 50 quizzes and MUCH MUCH more in 2 weeks.
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Hope I helped!!

Olin [163]3 years ago

8 0

Hey, KLprsbobsimas!
Yes, you can do 50 quizzes in 2 weeks. You have 25 quizzes per week, and each takes 5 minutes.
25*5=125 minutes each week.
I hope this helps;)

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Can somebody please solve this for me and show the work? it doesn't look too hard I'm just dumb.

lana [24]

Answer:

x = 7

Step-by-step explanation:

vertical angles are pairs of opposite angles made by intersecting lines. and they are congruent

x + 16 = 4x - 5

x - 4x = - 5 - 16

- 3x = - 21

- x = - 21/3

- x = - 7

x = 7

hope it helps

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8 0

3 years ago

Find the distance between the two points (-2,-6) and (0,5).

HACTEHA [7]

Answer: OPTION B

Step-by-step explanation:

You can find the distance between two points by using the following formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given the points (-2,-6) and (0,5), you can identify that:

$x_2=-2\\x_1=0\\\\y_2=-6\\y_1=5$

Therefore, substituting values, you get that the distance between those points is:

$d=\sqrt{(-2-0)^2+(-6-5)^2}\\\\d=5\sqrt{5}$

7 0

3 years ago

Read 2 more answers

Find a polynomial function of least degree having only real coefficients, a leading coefficient of 1, and roots of 2-√6 , 2+ √6

horsena [70]

Answer:

$x^{4} -18x^{3}+104x^{2} -172x-100$

Step-by-step explanation:

The 3 roots are given out of which 2 are real and 1 is imaginary. For a polynomial of least degree having real coefficients, it must have a complex conjugate root as the 4th root. Therefore, based on 4 roots, the least degree of polynomial will be 4. Finding the polynomial having leading coefficient=1 and solving it based on multiplication of 2 quadratic polynomials, we get:

$\\\\x_{1} = 2-\sqrt{6} \\x_{2} = 2+\sqrt{6} \\x_{3}=7-i \\x_{4}=7+i \\\\P(x)=1(x-x_{1})(x-x_{2} )(x-x_{3} )(x-x_{4} ) \\\\=(x-(2-\sqrt{6}))( x-(2+\sqrt{6} )) (x-(7-i))( x-(7+i))\\=((x-2)+\sqrt{6})( ( x-2)-\sqrt{6} ) ((x-7)+i)( (x-7)-i)\\=((x-2)^{2} -(\sqrt{6} )^{2} )((x-7)^{2}-(i)^{2})\\=(x^{2} -4x-2)(x^{2} -14x+50)\\=x^{4} -18x^{3}+104x^{2} -172x-100\\$