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SSSSS [86.1K]
3 years ago
8

Can I do 50 quizzes in 2 weeks? Each takes about 5 minutes

Mathematics
2 answers:
rodikova [14]3 years ago
8 0
So.
.
Let's get started with formulas.
.
I KNOW you hate formulas!! So do I, but we have to use them. No "buts". 
.
So, how many minutes are in 2 weeks?
.
Search it up. For your convenience, it is 20,160 minutes.
.
Well, I think you have your answer, since each quiz is 5 minutes, 5 times 50 (5 x 50) is 2,500 minutes.
.
Yes, you can do 50 quizzes and MUCH MUCH more in 2 weeks.
.
Hope I helped!!
Olin [163]3 years ago
8 0
Hey, KLprsbobsimas!
Yes, you can do 50 quizzes in 2 weeks. You have 25 quizzes per week, and each takes 5 minutes.
25*5=125 minutes each week.
I hope this helps;)
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Ivanshal [37]

Answer:

area of sector dfe=(360-110)/360×πr²=250/360×22/7×4²=34.9=35ft²

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A bag contains 2 red, 4 blue, and 4 yellow marbles. What is the probability of pulling a red marble, putting the marble back, an
Xelga [282]

Answer:

Red: 1/5 or 0.2 or 20% (depends if the question asked you to give the answer in fraction/decimal/percentage. Either way, it's still correct)

Black: 0

Blue: 2/5 or 0.4 or 40%

Step-by-step explanation:

In total, the bag contains 10 balls,

  • 2 are Red = 2/10 = 1/5

  • There are no black marbles so you have 0 chance of pulling them out.

  • 4 are blue = 4/10 = 2/5
7 0
2 years ago
Question part points submissions used as a science project, you drop a watermelon off the top of the empire state building, 320
Nataly [62]
We are given a watermelon dropped at free fall from a building 320 meters above the sidewalk. Superman is headed down at 30 meters per second. We are asked to determine how fast is the watermelon going when it passes Superman. To solve for the final velocity of the watermelon, we will use one of the kinematic equations (free fall):

vf = vi + a*t

where vf is the final velocity
            vi is the initial velocity, zero
            a is the acceleration, in this case, gravitational acceleration = 9.8m/s^2
            t is time

we also need to set-up another equation using the distance:

d = vf + vi / 2 * t

(1) 320 m = vf * t /2

(2) vf = 9.8 m/s^2 * t

From here, we have two equations and two unknown, thus we can solve the problem by substitution. 

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8 0
3 years ago
What are two solutions of 3 + 4 |x/2 + 3| = 11?
Alex
3 + 4abs(x/2 + 3) = 11 Subtract 3
4 abs(x/2 + 3) = 11 - 3
4 abs(x/2 + 3) = 8 Divide by 4
abs(x/2 + 3) = 8/4
abs(x/2 + 3) = 2

Solution 1
x/2 + 3 = 2 Subtract 3
x/2 = 2 - 3
x/2 = - 1 Multiply by 2
x/2 *2 = - 2
x = - 2

Solution 2
x/2 + 3 = - 2
x/2 = - 2 - 3
x/2 = - 5 Multiply by 2
x = -5 * 2
x = -10

Solutions
x = - 2 <<<< answer 1
x = -10 <<<< answer 2

3 0
3 years ago
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