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3 years ago

Can I do 50 quizzes in 2 weeks? Each takes about 5 minutes

2 answers:

8 0

So.
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Let's get started with formulas.
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I KNOW you hate formulas!! So do I, but we have to use them. No "buts".
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So, how many minutes are in 2 weeks?
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Search it up. For your convenience, it is 20,160 minutes.
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Well, I think you have your answer, since each quiz is 5 minutes, 5 times 50 (5 x 50) is 2,500 minutes.
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Yes, you can do 50 quizzes and MUCH MUCH more in 2 weeks.
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Hope I helped!!

Olin [163]3 years ago

8 0

Hey, KLprsbobsimas!
Yes, you can do 50 quizzes in 2 weeks. You have 25 quizzes per week, and each takes 5 minutes.
25*5=125 minutes each week.
I hope this helps;)

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A gumball has a diameter that is 66 mm. The diameter of the gumball's spherical hollow core is 58 mm. What is the volume of the

grigory [225]

Answer:

Volume of gumball without including its hollow core is 48347.6 cubic mm.

Step-by-step explanation:

Given:

Diameter of Gumball = 66 mm

Since radius is half of diameter.

Radius of gumball = $\frac{diameter}{2}=\frac{66}{2} =33 \ mm$

Now We will first find the Volume of Gumball.

To find the Volume of Gumball we will use volume of sphere which is given as;

Volume of Sphere = $\frac{4}{3}\pi r^3$

Now Volume of Gumball = $\frac{4}{3}\times3.14 \times (33)^3 = 150456.24 \ mm^3$

Also Given

Diameter of gumball's spherical hollow core = 58 mm

Since radius is half of diameter.

Radius of gumball's spherical hollow core = $\frac{diameter}{2}=\frac{58}{2} =29 \ mm$

Now We will find the Volume of gumball's spherical hollow core.

Volume of Sphere = $\frac{4}{3}\pi r^3$

So Volume of gumball's spherical hollow core = $\frac{4}{3}\times3.14 \times (29)^3 = 102108.61 \ mm^3$

Now We need to find volume of the gumball without including its hollow core.

So, To find volume of the gumball without including its hollow core we would Subtract Volume of gumball spherical hollow core from Volume of Gumball.

volume of the gumball without including its hollow core = Volume of Gumball - Volume of gumball's spherical hollow core = $150456.24\ mm^3 - 102108.61\ mm^3 = 48347.63\ mm^3$

Rounding to nearest tenth we get;

volume of the gumball without including its hollow core = $48347.6\ mm^3$

Hence Volume of gumball without including its hollow core is 48347.6 cubic mm.

8 0

3 years ago

The number of responses to a survey are shown in the Pareto chart. The survey asked 1052 adults how they would grade the quality

Goryan [66]

Answer: (a) P(no A) = 0.935

(b) P(A and B and C) = 0.0005

(d) P(A or B) = 0.31

Step-by-step explanation: <u>Pareto</u> <u>Chart</u> demonstrates a relationship between two quantities, in a way that a relative change in one results in a change in the other.

The Pareto chart below shows the number of people and which category they qualified each public school.

(a) The probability of a person not giving an A is the difference between total probability (1) and probability of giving an A:

P(no A) = $1-\frac{68}{1052}$

P(no A) = 1 - 0.065

P(no A) = 0.935

b) Probability of a grade better than D, is the product of the probabilities of an A, an B and an C:

P(A and B and C) = $(\frac{68}{1052})(\frac{258}{1052})(\frac{327}{1052})$

P(A and B and C) = $\frac{5736888}{1164252608}$

P(A and B and C) = 0.0005

c) Probability of an D or an F is the sum of probabilities of an D and of an F:

P(D or F) = $\frac{269}{1052} +\frac{130}{1052}$

P(D or F) = $\frac{399}{1052}$

P(D or F) = 0.379

d) Probability of an A or B is also the sum of probabilities of an A and of an B:

P(A or B) = $\frac{68}{1052} +\frac{258}{1052}$

P(A or B) = $\frac{326}{1052}$

P(A or B) = 0.31

7 0

3 years ago

Draw a model to represent the problem 6/12 divided by 1/4

Sloan [31]

0.5/0.25?

Not really sure what ur asking

5 0

3 years ago

Hey, help me with this pls i only have 10 minutes. 30 points each :)

vlada-n [284]

Answer:

y=-2x

Step-by-step explanation:

First you want to remember rise over run. Your rise is -2 and your run is 1. So -2/1 is your answer. And -2/1 is equal to -2.

7 0

3 years ago

Read 2 more answers

Select Exponential growth or Exponential decay for each function.

Lena [83]

Answer:

f(x)=(1.023) ⋅ 3^x Growth

f(x)=3 ⋅ (0.072)^x Decay

f(x)=4 ⋅ (0.035)^x Decay

f(x)=2 ⋅ (1.34)^x Growth

Step-by-step explanation:

An exponential function at its heart has a base number of rate. If the rate is less than 1, then the function decays. If the base number or rate is greater than 1, then the function grows and increase.

f(x)=(1.023) ⋅ 3^x Rate 3 - Growth

f(x)=3 ⋅ (0.072)^x Rate 0.072 - Decay

f(x)=4 ⋅ (0.035)^x Rate 0.035 - Decay

f(x)=2 ⋅ (1.34)^x Rate 1.34 - Growth

7 0

3 years ago