I'd say the answer to the first question is D) 0 to 4 with intervals of 0.2.
Because, you can't just have 1 to 4, as some of the numbers are less than 1. Of course you can't have 2 to 5 either. And intervals of 2 would be too messy.
For the second question:
I believe the answer is A. Because it's obvious that there IS one outlier, and it looks like there are two clusters.
So, the answers are: A) and D).
Answer:
1. 34.42 Toneladas
2. 28.640 toneladas
3. 38 toneladas
4.
o 
5.
o 
6.
o 
1.1 Solucioné el problema convirtiendo el .25 en fracción.
2.1 Conviertes el denominador en el mismo buscando el minimo comun multiplo
3.1 0.099



0.7
0.75
1.1

Step-by-step explanation:
Acuerdate que para solucionar las fracciones mixtas solo tienes que dividir el denominador al nominador, por ejemplo en si tienes
entonces el 3 cabe 3 veces en el 10, y sobra 1, entonces quedamos que en mixta la fracción sería 
Entonces una vez que recordamos eso, podemos resolver los problemas de fracciones sin ningún problema vamos a resolver la número 4:

Como el denominador es igual, sólo sumamos el nominador:


Cómo el 10 cabe 1 vez en el 15, tenemos un entero y sobran 5:

Answer:
174 square centimetres
Step-by-step explanation:
The formula for finding the surface area of a rectangular prism is
SA = 2LW + 2LH + 2HW
Therefore surface area will be
= 2(11*5) + 2(11*2) +2(2*5)
= 2 * 55 + 2 * 22 + 2 * 10
= (110 + 44 + 20) square cm
Which gives you 174 square centimetres.
We cannot calculate the confidence interval without the sample size. However, for the second question, the sample size needed would be 49.
The formula we use is

To find the z-score:
Convert 98% to a decimal: 0.98
Subtract from 1: 1-0.98 = 0.02
Divide by 2: 0.02/2 = 0.01
Subtract from 1: 1-0.01 = 0.99
Using a z-table (http://www.z-table.com) we see that this value is closest to a z-score of 2.33.
Using the z-score, our standard deviation (9) and our margin of error (3), we have:
None of the offered choices is correct.
The radical cannot be simplified. If rewritten, it must be written as something like
![x \sqrt[3]{ \frac{6}{x}}](https://tex.z-dn.net/?f=%20x%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B6%7D%7Bx%7D%7D%20)
or