<h3>Given that it is arithmetic</h3>


Answer:
Option E 15 cm
Step-by-step explanation:
we know that
The circumference of a circle subtends a central angle of 360 degrees
so
using proportion
Find out the length of arc DE by a central angle of 45 degrees
Let
x -----> the length of arc DE

It would be a 50/50 chance that all of them would be girls
Answer:

Step-by-step explanation:
Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin)
.
We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63
b = ±√(a² - c²)
= ±√(91² - 63²)
= ±√(8281 - 3969)
= ±√4312
= ±14√22
So the equation is
