Answer:
don't
Step-by-step explanation:
please send me only
Answer:
The coordinates of H′ are (-2,0).
Step-by-step explanation:
It is given that square EFGH stretches vertically by a factor of 2.5 with respect to the x-axis to create rectangle E′F′G′H′.
If a figure stretches vertically by a factor of 2.5 with respect to the x-axis, then the x-coordinates remains same and the points which lie on the axis are also remains the same after stretch.
It is given that the coordinates of H are (-2,0). This point lie on the x-axis, therefore it will remains the same after stretch.
Therefore the coordinates of H′ are (-2,0).
Answer:
![(1) = 38\°](https://tex.z-dn.net/?f=%281%29%20%3D%2038%5C%C2%B0)
![(2) = 90\°](https://tex.z-dn.net/?f=%282%29%20%3D%2090%5C%C2%B0)
![(3) = 90\°](https://tex.z-dn.net/?f=%283%29%20%3D%2090%5C%C2%B0)
![(4) = 38\°](https://tex.z-dn.net/?f=%284%29%20%3D%2038%5C%C2%B0)
Step-by-step explanation:
The diagonals of a rhombus are perpendicular to each other, so angles (2) and (3) are equal 90°.
To find angle (1), we can use the sum of internal angles in the left triangle with angles 52°, (1), and (2):
![52 + (1) + (2) = 180](https://tex.z-dn.net/?f=52%20%2B%20%281%29%20%2B%20%282%29%20%3D%20180)
![(1) = 180 - 52 - 90](https://tex.z-dn.net/?f=%281%29%20%3D%20180%20-%2052%20-%2090)
![(1) = 38\°](https://tex.z-dn.net/?f=%281%29%20%3D%2038%5C%C2%B0)
The diagonals of a rhombus bisects the angles, to the angle next to the angle of 52° is also 52°, then, in the upper triangle, we have:
![52 + (4) + 90 = 180](https://tex.z-dn.net/?f=52%20%2B%20%284%29%20%2B%2090%20%3D%20180)
![(4) = 38\°](https://tex.z-dn.net/?f=%284%29%20%3D%2038%5C%C2%B0)
Answer:
3
Step-by-step explanation: So first you have to make this word problem into a equation into standard form so 20 is our (y) because that is the additional charge but our slope is 3 because that is what they charge per hr **when they say (per) usually the member with it is the slope** (sry I’m not the best explainer)
Answer:
5-13 = -8
Step-by-step explanation: