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3 years ago

PLEASE HELP! TWO PROBLEMS!!

Mathematics

1 answer:

MrRissso [65]3 years ago

6 0

1) x=−2 2) y=−6 Hopefully that helps you ❤.

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A movie theater charges $12.00 for adults and $4.50 for children under the age of ten. A group of adults and children went to th

Shtirlitz [24]

Answer:

4 Adults and 6 Children went to the movies.

Step-by-step explanation:

(Children) $4.50 x 6 = $27.00

(Adults) $12.00 x 4 = $48.00

$48.00 + $27.00 = $75.00

5 0

3 years ago

There were 40 fingers total on the number of gloves Mrs. Edwards knitted. How many gloves did Mrs.Edward knit.

GarryVolchara [31]

40 ÷10 = 4

Mrs Edward knitted 4 pairs of gloves.

7 0

3 years ago

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Are the following lines parallel, perpendicular, or neither: y=-x+6 and y=x+1

Artist 52 [7]

Answer:

The following lines is perpendicular, y=-x+6 and y=x+1

Step-by-step explanation:

Slope of parallel lines are equal

(ex. slope of 2 stays 2 )

Slope of perpendicular lines to another is the negative reciprocal

(ex. slope of 2 becomes -1/2)

y = -x + 6 and y = x + 1

the slope for y = -x + 6 is <em>-1 (-1/1)</em>

the slope for y = x + 1 is <em>1</em>

the slope -1 is the negative reciprocal of 1

hence, the definition of perpendicular fits the given

Learn more about Perpendicular and Parallel Lines here: brainly.com/question/1202004

7 0

2 years ago

Will finished 2/10 of his math homework on the school bus what percent did he finish on the bus

kenny6666 [7]

20% you will need to simplfy 2/10 by dividing it by 2 you will then get 1/5 after that you will divide 5 by 1 and and you will get 0.2 you will then move your decimal point over 2 places and you will get 20%

7 0

3 years ago

Read 2 more answers

WILL GIVE BRAINLIEST ANSWER!!

Natasha2012 [34]

Check the picture below.

now, bear in mind that, there are 60minutes in 1 degree, so 23' is just 23/60 degrees or about 0.38 degrees.

and 29' is just 29/60 degrees or about 0.48 degrees.

so 16°23' is about 16.38°, and 49°29' is about 49.48°

$\bf tan(16.38^o)=\cfrac{200}{a+b}\implies a+b=\cfrac{200}{tan(16.38^o)}
\\\\\\
\boxed{b=\cfrac{200}{tan(16.38^o)}-a}
\\\\\\
tan(49.48^o)=\cfrac{200}{b}\implies \boxed{b=\cfrac{200}{tan(49.48^o)}}\\\\
-------------------------------\\\\
\cfrac{200}{tan(49.48^o)}=\cfrac{200}{tan(16.38^o)}-a\\\\\\a=\cfrac{200}{tan(16.38^o)}-\cfrac{200}{tan(49.48^o)}$

make sure your calculator is in Degree mode.

4 0

3 years ago

Read 2 more answers