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Zolol [24]
2 years ago
11

200z + 50 = 8000 solve this problem

Mathematics
1 answer:
kramer2 years ago
8 0

Answer:

39.75

Step-by-step explanation:

First, subtract 50 from both sides

200z + 50 - 50 = 8000 - 50

200z = 7950

Then isolate the variable by dividing both sides by 200

200z/200 = 7950/200

z=39.75

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I need help plz and thank u sm
Alchen [17]

Answer:

5x + 3

Step-by-step explanation:

Since we can see DC is the median of Triangle ABC

So it breaks the into two equal parts

Given

AD = 2x + 5

BD = 3x - 2

Now

AB = AB + BD

= 2x + 5 + 3x - 2

= 5x + 3

Hope it will help :)❤

7 0
2 years ago
5 - 3x &gt; -19 <br> Can someone please help me
oksano4ka [1.4K]

Answer:

- 3x > -19 -5

- 3x > -24

3x < 24

x < 8

8 0
2 years ago
PLZ HELP WILL NAME BRIANLIEST
Kamila [148]

Answer:

SORRY IF IM WRONG BUT I THINK ITS C

Step-by-step explanation:

PLEASE MARK BRAINLIEST REMOVE MY ANSWER IF WRONG!!!!!!!!

3 0
3 years ago
The value of a certain car decreases by 16% each year. What is the 1⁄2-life of the car?
svet-max [94.6K]

Answer:

The half life of the car is 3.98 years.

Step-by-step explanation:

The value of the car after t years is given by the following equation:

V(t) = V(0)(1-r)^{t}

In which V(0) is the initial value and r is the constant decay rate, as a decimal.

The value of a certain car decreases by 16% each year.

This means that r = 0.16

So

V(t) = V(0)(1-r)^{t}

V(t) = V(0)(1-0.16)^{t}

V(t) = V(0)(0.84)^{t}

What is the 1⁄2-life of the car?

This is t for which V(t) = 0.5V(0). So

V(t) = V(0)(0.84)^{t}

0.5V(0) = V(0)(0.84)^{t}

(0.84)^{t} = 0.5

\log{(0.84)^{t}} = \log{0.5}

t\log{0.84} = \log{0.5}

t = \frac{\log{0.5}}{\log{0.84}}

t = 3.98

The half life of the car is 3.98 years.

7 0
3 years ago
Find the equation of the line through point (3,−3) and parallel to y=3x−4. Use a forward slash (i.e. "/") for fractions (e.g. 1/
exis [7]

Answer:

y =3x - 12

Step-by-step explanation:

I'm fairly certain this is the answer.

Consider the point (3,-3). In terms of variables this is written (x,y).

Remember that the equation for slope is y = mx + b.

In that equation, "b" is your y-intercept, and "m" is your slope.

If 2 lines are parallel, they have the same slope but different y-intercepts. So you can use the slope from the equation y=3x-4 to find the parallel line. You can also plug in the values 3 and -3 to solve for b, our y-intercept.

If we set up the equation, we have -3 = 3(3) + b.

Now solve for b.

-3 = 9 + b

Combine like terms, so that -12 = b, and you have your y-intercept.

To create the equation, take out the coordinate pair that the line passes through, and only have the SLOPE and the Y-INTERCEPT showing in the equation.

Therefore, y = 3x - 12

5 0
3 years ago
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