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Y_Kistochka [10]
3 years ago
10

Find the surface area of the cylinder.

Mathematics
2 answers:
Stolb23 [73]3 years ago
7 0
Hi how are you doing today Jasmine
Ronch [10]3 years ago
4 0

Answer:

exact: 48pi cm^2

approximate: 150.8 cm^2

Step-by-step explanation:

SA = 2 * (pi)r^2 + 2(pi)rh

SA = 2 * pi * (3 cm)^2 + 2(pi) * 3 cm * 5 cm

SA = pi(18 cm^2 + 30 cm^2)

SA = 48pi cm^2

SA = 150.8 cm^2

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RoseWind [281]

Step-by-step explanation:

-1,6 is -1 left 6 up

1,-6 is 1 right -6 down

6,-1 is 6 right -1 down

3 0
3 years ago
The cost of 20⅕ oranges is rs 300,what is the cost of a kg oranges?​
JulijaS [17]

Answer:

weight not defined

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The cost of 20⅕ oranges is rs 300 ,what is the cost of a kg oranges?

HOW ARE WE SUPPOSE TO KNOW THE WEIGHT IF ONLY THE PRICE IS GIVEN

5 0
2 years ago
Create a matrix that is equal to F+G. The first matrix below is named F and the second matrix below is named G. Name the new mat
likoan [24]

F+G:

F+G=\begin{bmatrix}{-1.8} & {-8.6} & {} \\ {2.85} & {-1.4} & {} \\ {-1.8} & {5.1} & {}\end{bmatrix}+\begin{bmatrix}{1.32} & {-1.9} & {} \\ {2.25} & {0.0} & {} \\ {-6.2} & {1.4} & {}\end{bmatrix}

Then, add the elements that occupy the same position:

H=\begin{bmatrix}{-1.8+1.32} & {-8.6+(-1.9)} & {} \\ {2.85+2.25} & {-1.4+0.0} & {} \\ {-1.8+(-6.2)} & {5.1+1.4} & {}\end{bmatrix}

Solve

H=\begin{bmatrix}{-0.48} & {-10.5} & {} \\ {5.1} & {-1.4} & {} \\ {-8} & {6.5} & {}\end{bmatrix}

So, we find the element at address h31:

H=\begin{bmatrix}{h11} & {h12} & {} \\ {h21} & {h22} & {} \\ {h31} & {h32} & {}\end{bmatrix}

In this case, position h31 is - 8.0

8 0
1 year ago
What's the lateral area of a right circular cone if the diameter of the base is 4 m and the slant height of the cone is 15m? Rou
Mekhanik [1.2K]
The formula for the lateral surface area of a right circular cone is:
\pi rl
where r is the radius of the base, and l is the slant height.
Plugging in the values we get:
Lateral\  area= \pi \times \frac{4}{2} \times15\  m^{2}
5 0
3 years ago
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