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Keith_Richards [23]
3 years ago
14

HELP ive been asking for hpurs be SERIOUS

Mathematics
1 answer:
babunello [35]3 years ago
3 0

Answer:

27 will be UR answer

Step-by-step explanation:

mark it faster

xy/xz = pq/pr

6/9 = 18/X

X = 27

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Do the side lengths 15,20 and 25 form a right triangle?<br><br><br> PLEASEEEE HELPPPP!!! asap
sveticcg [70]
<h3>Answer: Yes, those sides form a right triangle</h3>

===================================================

Work Shown:

a^2+b^2 = c^2

15^2+20^2 = 25^2

225+400 = 625

625 = 625

Since the last equation is true, this makes the first equation true for those a,b,c values. Therefore, by the pythagorean theorem converse, this is a right triangle.

Side note: c is always the longest side.

6 0
3 years ago
Rectangular windows are being made into a wall of windows for an office building. Each wall is 14 feet tall and 12 feet wide. Th
Artemon [7]

Answer:

  168/(x² +7x)

Step-by-step explanation:

The height of each window is 14/(x+7), and the width of each window is 12/x. The area of each window is the product of its height ans width:

  area = (14/(x+7))(12/x) = 168/(x(x +7))

  area = 168/(x² +7x)

_____

<em>Comment on the problem</em>

There is not enough information given to determine suitable values for x. If x is 42, each window is a square 3 3/7 inches on a side.

7 0
3 years ago
Evaluate 5! + 2!.<br> Idk what is it
Sedbober [7]

Answer:

122

Step-by-step explanation:

If a number has an explanation point on the side of it, you should multiply all numbers that are equal to are less than that number.

5!=5*4*3*2*1=120\\2!=2*1=2\\120+2=122

4 0
3 years ago
What is the square root of -121​
Savatey [412]

Answer: sqrt (-121) is 11i

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
3) x2+ y2 - x + 3y - 42 = 0<br> X+y=4
REY [17]

The solution is (-1,5) and (7,-3)

Step-by-step explanation:

The expression is x^{2} +y^{2} -x+3y-42=0 and x+y=4

Using substitution method we can solve the expression.

Let us substitute x=4-y in x^{2} +y^{2} -x+3y-42=0

(4-y)^{2} +y^{2} -(4-y)+3y-42=0

Expanding and simplifying the expression, we get,

\begin{array}{r}{16-8 y+y^{2}+y^{2}-4+y+3 y-42=0} \\{2 y^{2}-4 y-30=0}\end{array}

Let us use the quadratic equation formula to solve this equation,

\begin{aligned}y &=\frac{4 \pm \sqrt{16-4(2)(-30)}}{2(2)} \\&=\frac{4 \pm \sqrt{16+240}}{4} \\&=\frac{4 \pm 16}{4} \\y &=1 \pm 4\end{aligned}

Thus, y=5 and y=-3

Substituting y-values in the equation x+y=4, we get the value of x.

For y=5 ⇒ x=4-5=-1

For y=-3 ⇒ x=4+3=7

Thus, the solution set is (-1,5) and (7,-3)

7 0
4 years ago
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