Answer:
a = p * q
b = p * s + q * r
c = r * s
Step-by-step explanation:
In the trinomial ax² + bx + c
a is the coefficient of x²
b is the coefficient of x
c is the numerical term
∵ The trinomial is ax² + bx + c
∵ Its factors are (px + r) and (qx + s)
∴ ax² + bx + c = (px + r)(qx + s)
∵ (px + r)(qx + s) = (px)(qx) + (px)(s) + r(qx) + (r)(s)
∴ (px + r)(qx + s) = pqx² + (psx + qrx) + rs
∴ ax² + bx + c = pqx² + (ps + qr)x + rs
→ By comparing the two sides
∵ ax² = pqx² ⇒ divide both sides by x²
∴ a = pq
∵ bx = (ps + qr)x ⇒ Divide both sides by x
∴ b = ps + qr
∴ c = rs
∴ a = p * q
∴ b = p * s + q * r
∴ c = r * s
Answer:
x=2
Step-by-step explanation:
x-5=5x-13
5x-x=-5+13
4x=8
x=8/4
x=2
Answer: 576.09
Step-by-step explanation:
First number = 5.19.
The second number was 10 times the first number which will be:
= 5.19 × 10
= 51.9
The third number was 10 times the second number. Thus will be:
= 51.9 × 10
= 519
The sum of the numbers will be:
= 1st number + 2nd number + 3rd number
= 5.19 + 51.9 + 519
= 576.09
Well whats theproblem so we can figure it out?
I think the answer is 2x10^1
