Answer:
Yes, Triangles in (1) are congruent
Step-by-step explanation:
Two conditions must be satisfied before two triangles can be deemed or declared as being congruent.
1.) They must posses similar shape
2.) They must posses similar size ( that is the corresponding sides and angles of both triangles must be the same)
Triangles in (1) meet both criterias by possessing similar shape with the size and length of the corresponding angles also being the same.
Therefore, the two triangles are congruent.
Answer:
33.1698
Step-by-step explanation:
10
∫ 13y/ y^2-9y-22 .dy
-1
Let's break down the fraction first before we integrate
13y/ y^2-9y-22
= 13y/(y-11)(y+2)
=11/(y-11) + 2/(y+2)
Time to Integrate.
10
∫ 13y/ y^2-9y-22 .dy
-1
=∫ 11/(y-11) dy+ ∫ 2/(y+2) Dy
= 11In(y-11) + 2 In(y+2)
When y = 10
= 11In(10-11) + 2In(10+2)
= 11In1 + 2In12
= 4.9698
When y = -2
= 11In(y-11) + 2 In(y+2)
= 11In(-2-11) + 2In(-2+2)
= -28.2
4.9698+28.2= 33.1698
First we have to find the amount of area the paint needs to cover. We do this by doing 8*3=24. Next we divide 24 by 6 to find how many cans are needed. Therefore, the answer is 4 cans of paint.
Subtract 7 from each side
x=12
There are a lot of points. which points do you want?
minimum is (3/14 , 1,6785) ; (2,24) ; (-3,74)........