This can be mathematically expressed to
250 + X = 1075
where X represents the parts you produce before the shift ends
Transpose 250 to the other side by subtracting each side by 250
Thus, it goes like this
X = 1075 - 250
X = 825
You produced 825 parts in the middle of the shift.
Answer:
If it's reflected on the y-axis, the answer for N would be (-2,-3).
Solve the area of the whole circle since in an hour, the minute hand covers the whole clock
assuming that the minute hand reaches all the way out to the edge of the clock
the minute hand is the radius
area=pi times r^2
r=5
5^2=25
area=pi times 25
area=25pi
aprox pi=3.14
25 times 2.14=78.5
area=78.5 in^2
The area of the entire sector is ![(\pi)(6^{2}) \left(\frac{60}{360} \right)=6\pi](https://tex.z-dn.net/?f=%28%5Cpi%29%286%5E%7B2%7D%29%20%5Cleft%28%5Cfrac%7B60%7D%7B360%7D%20%5Cright%29%3D6%5Cpi)
The area of the triangle OAB is
.
So, the area of the segment is ![\boxed{6\pi-9\sqrt{3}}](https://tex.z-dn.net/?f=%5Cboxed%7B6%5Cpi-9%5Csqrt%7B3%7D%7D)
BC I WONT DONT HAVE TO DO MY WORK