9x+10= 21
Please give me thanks and brainliest, this took lots of hard work and dedication
Answers:
1.)
C - Final exams: midterm = Q3 92 - Q1 80 = 12 and finals = Q3 85 - Q1 78 = 7, so finals exam has the smaller IQR.
2.)
B - exam median is much higher than the class median: refer to the attached image of class and exam box and whisker graph
3.)
A - <span>
IQR is a better measure of spread for movies than it is for basketball games: because the data for movies are quite wide or apart from each other than the data in the basketball games
4.)
A - </span><span>
mean for April is higher than October's mean: mean in April is 67 and mean in October is 60
5.)
A - </span><span>
Neither data set has suspected outliers: meaning there's no data that is further apart from the group or set
6.)
B - </span>
There is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical
<span>
7.)
C - </span>
college spread is best described by the IQR. The high school spread is best described by the standard deviation: this is because of the wide range of data in the college than the data in the high school.
Fill in the blanks to show the product number 1X2
Answer:
m∠APC = 30°
Step-by-step explanation:
To solve for the above question, we would be making use of circle theorems
Looking at the circle, we can see that
m∠APC is an Angle outside the circle
m∠AOC is a smaller arc in the circle.
Therefore, Circle Theorem states that for a circle with two tangents,
The Angle outside the circle + The smaller arc = 180°
Hence,
m∠AOC + m∠APC = 180°
m∠APC = 180° - m∠AOC
m∠APC = 180° - 150°
m∠APC = 30°
Step-by-step explanation:
(1/12)^-2b x 12^-2b+2=12
12^-(-2b) x 12^-2b+2=12
12^2b+(-2b+12)=12
2b-2b+12=12
=1