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3 years ago

Solve the equation A+b - c =180 for C

Mathematics

1 answer:

spayn [35]3 years ago

5 0

A = 180
b = 180
c = 180

180+180-180 = 180

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Five of Teddy’s six cousins can

Sliva [168]

Answer: 0.83

Step-by-step explanation:

The fraction of Teddy's cousins what can do push-ups is $\frac{5}{6}$ . We get this fraction because the problem states that 5 of Teddy's 6 cousins can do 15 push-ups. Now that we have our fraction, we divide to get our decimal.

$\frac{5}{6} =0.83$

7 0

3 years ago

50 people sponsor paula and she raises a total of £180 for charity. what is the mean average amount sponsored

mylen [45]

The mean is the average so 180/50 = 3.6 therefor the mean of each donation from each sponsor is £3.60

4 0

3 years ago

Read 2 more answers

Jim is enclosing a rectangular garden with 170 feet of fencing. The length of the garden is 10 feet more than twice it's width,

Hunter-Best [27]

Answer: Area = 1500 feet^2

Step-by-step explanation:

Jim is enclosing a rectangular garden with 170 feet of fencing. This means the perimeter of the rectangular garden =170 feet

Let length = x

Let width = w

The length of the garden,x is 10 feet more than twice it's width, w. This means

x =10+2w---------1

Perimeter = 2x+2w =170---------2

Putting equation 1 in equation 2,

2(10+2w) +2w= 170

20 + 4w +2w = 170

6w = 170-20=150

w = 150/6

= 25feet

Put w=25 in equation 1

x =10 +2×25= 10+50=60 feet

Area = length × width = x×w

= 60×25=1500feet^2

5 0

3 years ago

For the standard normal probability distribution, the area to the right of the mean is:

sveticcg [70]

The answer is 0.5. I hope this is helpful.

7 0

3 years ago

The length of human pregnancies from conception to birth varies according to an approximately normal distribution with a mean of

Varvara68 [4.7K]

Answer:

A) 68.33%

B) (234, 298)

Step-by-step explanation:

We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:

A. P (250 x < 282)

P ((x1 - m) / sd < x < (x2 - m) / sd)

P ((250 - 266) / 16 < x < (282 - 266) / 16)

P (- 1 < z < 1)

P (z < 1) - P (-1 < z)

If we look in the normal distribution table we have to:

P (-1 < z) = 0.1587

P (z < 1) = 0.8413

replacing

0.8413 - 0.1587 = 0.6833

The percentage of pregnancies last between 250 and 282 days is 68.33%

B. We apply the experimental formula of 68-95-99.7

For middle 95% it is:

(m - 2 * sd, m + 2 * sd)

Thus,

m - 2 * sd <x <m + 2 * sd

we replace

266 - 2 * 16 <x <266 + 2 * 16

234 <x <298

That is, the interval would be (234, 298)

6 0

2 years ago