Which shape is a continuous line of equal distance from its center?
1 answer:
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Answer:
x²/2166784 +y²/2159989 = 1
Step-by-step explanation:
The relationship between the semi-axes and the eccentricity of an ellipse is ...
e = √(1 -b²/a²)
In order to write the desired equation we need to find 'b' from 'e' and 'a'.
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<h3>semi-minor axis</h3>Squaring the equation for eccentricity gives ...
e² = 1 -b²/a²
Solving for b², we have ...
b²/a² = 1 -e²
b² = a²(1 -e²)
<h3>ellipse equation</h3>Using the given values, we find ...
b² = 1472²(1 -0.056²) = 2166784(0.996864) ≈ 2159989
The desired equation is ...
x²/2166784 +y²/2159989 = 1
