Which shape is a continuous line of equal distance from its center?

During his hike milt drank 1 liter of water and 1 liter of sports drink how many milliliters of liquid did he drink

a_sh-v [17]

In total, he drank 2 liters.

In millimeters, this is:
2,000 milliliters.

1 liter = 1,000 milliliters
2 liters = 1,000×2
= 2,000 millimetres

3 0

3 years ago

F(x)=x^2+3x+2 is shifted 2 units left.the result is g(x). What is g(x)?

slamgirl [31]

Answer:

Either A or B.

Step-by-step explanation:

When shifting to the left you are adding to x.

Example: x^2 shifted to the left by 3. (x+3)^2

6 0

3 years ago

Read 2 more answers

A Norman window has the shape of a semicircle atop a rectangle so that the diameter of the semicircle is equal to the width of t

Makovka662 [10]

Answer:

132.233 ft2

Step-by-step explanation:

Let's call the width of the rectangle 'w' and the length 'x'. So the area of the semicircle is:

$A_1 = \pi*radius^2/2$

$A_1 = \pi*(w/2)^2/2$

$A_1 = \pi/8*w^2$

And the area of the rectangle is:

$A_2 = w*x$

If the perimeter of the window is 41 feet, we have:

$Perimeter = length + 2*width + \pi*radius$

$41 = x + 2*w + \pi*w/2$

$x = 41 - w(2 + \pi/2)$

Now, the equation for the total area of the window is:

$A = A_1 + A_2 = \pi/8*w^2 + w*x$

$A = \pi/8*w^2 + w*(41 - w(2 + \pi/2))$

$A = (\pi/8-2 - \pi/2)*w^2 + 41w = -3.1781w^2 + 41w$

To find the maximum area, we can find the x-coordinate of the vertex of the quadratic equation:

$x\_vertex = -b / 2a = -41 / (-3.1781*2) = 6.45$

So the width that gives us the maximum area of the window is 6.45 feet, and the area will be:

$A = -3.1781w^2 + 41w = -3.1781*(6.45)^2 + 41*6.45 = 132.233\ ft^2$

3 0

3 years ago

URGENT

kupik [55]

The best way to approach this problem is to look at the graph of the given function. Replace values of x from 1 to 24 to indicate the numbers of hours in a day. As seen on the graph, there is only one point where the port is at high tide. That would be at 1:00 am.

Looking at the graph, it would be safe for the boats to be in the port when the graph levels off at around 10 to 24. That's from 10 am to before 12 midnight. Then, they would have to stay away between 12 midnight to before 10 am.

6 0

3 years ago

If you wanted to find the mean height of students in an elementary school,

Kryger [21]

It is not possible to select a single group from the primary school, since being a single group it could not in any way represent the entire primary school.

Choosing a group would provide the average height for that group, not the entire primary.

Assumptions can be made that the course of half of the primary would theoretically give us a more accurate representation, but the objective is to select a number of students from each course and there would be a representative sample of the entire primary.

6 0

4 years ago