The answer to this question will be D
Answer:
= -6
Step-by-step explanation:
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Answer:
x = -2
Step-by-step explanation:
hope this helps you
Answer:
The answer is "Option A and Option B".
Step-by-step explanation:
In question 1:
In all cases, the entire population is measured so that the actual medium discrepancy could be measured as well as an interval of trust cannot be used.
This issue would be that she calculated the ages with all representatives of both classes, such that she measured a whole population. It's not necessary.
In question 2:
When the p-value is 0.042. At 90% trust and 92% trust level 11 (p-value below 0.10 and 0.08) are not included. however the biggest confidence level of 92%. Consequently, the largest trust level where the 11 is Not included in the trust interval is 92% trust.
Area is 6000 yd2
LW = 6000
field must be 40 yards longer than its width
L = W + 40
Replace L with W+40 in 1st equation to solve for Width
(W+40)(W) = 6000
W2 + 40W - 6000 = 0
This is a quadratic but is factorable
Factors of -6000 that add to 40 are (100)(-60)
(W+100)(W-60) = 0
W = -100 or W = 60
Since the width will not be negative discard -100
The width is 60 yards
Length is W+40 = 100 yards