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Aleks [24]
3 years ago
7

Which THREE side lengths CAN NOT make a triangle

Mathematics
2 answers:
Norma-Jean [14]3 years ago
5 0

Answer: 6m, 10m, and 21m

Step-by-step explanation:

The two smaller sides have to add to be greater than the third side. 6+10 is 16 which is smaller than 21.

BigorU [14]3 years ago
4 0

Answer: D. 21cm  

Step-by-step explanation: because you divide all sides by 2 then get youe slope form and multiply by seven

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Line A is perpendicular to line B. The slope of line A is -1/9 what is the slope of line b?
Pani-rosa [81]
\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}}
{\stackrel{slope}{-\cfrac{1}{9}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{9}{1}}\qquad \stackrel{negative~reciprocal}{+\cfrac{9}{1}}\implies 9}
4 0
3 years ago
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QUESTION 7.
Elan Coil [88]

The probability that exactly 4 of the selected adults believe in reincarnation is 5.184%, and the probability that all of the selected adults believe in reincarnation is 7.776%.

Given that based on a poll, 60% of adults believe in reincarnation, to determine, assuming that 5 adults are randomly selected, what is the probability that exactly 4 of the selected adults believe in reincarnation, and what is the probability that all of the selected adults believe in reincarnation, the following calculations must be performed:

  • 0.6 x 0.6 x 0.6 x 0.6 x 0.4 = X
  • 0.36 x 0.36 x 0.4 = X
  • 0.1296 x 0.4 = X
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  • 0.05184 x 100 = 5.184

  • 0.6 x 0.6 x 0.6 x 0.6 x 0.6 = X
  • 0.36 x 0.36 x 0.6 = X
  • 0.1296 x 0.6 = X
  • 0.07776 = X
  • 0.07776 x 100 = 7.776

Therefore, the probability that exactly 4 of the selected adults believe in reincarnation is 5.184%, and the probability that all of the selected adults believe in reincarnation is 7.776%.

Learn more in brainly.com/question/795909

5 0
2 years ago
In ABC, BC = a = 16, AC = b = 10, and m = 22°. Which equation can you use to find the value of c = AB?
zhannawk [14.2K]
10 times 16 = C I hope this helps
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Part B:
Marina86 [1]
Negative 72.75 is your product. It is very simple once you understand it.
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Determine (without solving the problem) an interval in which the solution of the given initial value problem is certain to exist
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If either t=0 or t=9, the ODE has the trivial solution y=0, but y(1)=1\neq0. So any solution to the ODE that satisfies the initial condition can only exist on the interval 0.

8 0
3 years ago
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