The formula for the vertical height, h, attained with a vertical take off speed of u is
u² - 2gh = 0
where
g = 9.8 m/s², acceleration due to gravity.
Because h = 1.29 m, therefore
u² = 2*9.8*1.39 = 27.244
u = 5.2196 m/s
Also, the time of flight, t, required when the vertical take-off speed is u is given by
ut - 0.5gt² = 0.
Therefore
5.2196t - 0.5*9.8*t² = 0
5.2196t - 4.9t² = 0
t(5.2196 - 4.9t) = 0
t = 0, or t = 5.2196/4.9 = 1.0652 s
t = 0 corresponds to take-off.
t = 1.0652 s corresponds to landing.
The hang time is 1.0652 s.
Answer:
Take-off speed = 5.22 m/s (nearest hundredth)
Hang time = 1.065 s (nearest thousandth)
Answer:
No Solution
Step-by-step explanation:
There are no values of x that make the equation true.
Answer:
b. False
Step-by-step explanation:
In a fixed-order-quantity system, when there is uncertainty in demand, the average demand will lead to a high probability of a stockout which is in contrast to what is stated in the question. Thus, the answer is false.
Answer:
When you make a payment on a simple interest loan, the payment first goes toward that month's interest, and the remainder goes toward the principal. Each month's interest is paid in full so it never accrues.
Step-by-step explanation:
Answer:
$353
Step-by-step explanation:
Step 1:
$552 - $82 - $117
Step 2:
$552 - $199
Answer:
$353
Hope This Helps :)
