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2 years ago

6

Why would one most likely use texting? A. to acquire information B. to explain feelings C. to get something desired D. to connec

t with others Please select the best answer from the choices provided A B C D

1 answer:

luda_lava [24]2 years ago

5 0

Answer:

d. connect with other people

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If 4/15 of the candies in a bag of Skittles are red and 3/10 are yellow, what fraction of the bag are red and yellow?

prohojiy [21]

The fraction of the bag are red and yellow are 17/30.

Add the two fractions together but first rewrite the fractions with a common denominator;

4/15 = 8/30;

3/10 = 9/30;

8/30 + 9/30 = 17/30;

To learn more about this; visit: brainly.com/question/24390812

#SPJ9

3 0

2 years ago

Fourteen less than the product of seven and a number.

Temka [501]

If the number that was multiplied by 7 is:

2: 0

3: 7

4: 14

5: 21

6: 28

7: 35

8: 42

9: 49

10: 56

4 0

3 years ago

Choose all the fractions that are equivalent to 1/7

valentinak56 [21]

2/14, 4/28, 5 /35, you must divide 2÷2/14/2 = 1/7

and of this form you must divide all the other fractions

5 0

4 years ago

Read 2 more answers

$74.00 sweatshirt; 5% tax<br> |

guapka [62]

Answer:

the tax amount is $3.7

Step-by-step explanation:

Given that

The price of the sweatshirt is $74

And, there is a 5% tax

So we assume that We need to find out the tax amount

So here the following formula should be used

= Price of the sweatshirt × tax rate

= $74 × 0.05

= $3.7

Hence, the tax amount is $3.7

So the same would be considered and relevant

3 0

3 years ago

Study the solutions of three equations on the right. Then complete the statements below.

Hoochie [10]

Answer:

Part 1) There are two real solutions

Part 2) There is one real solution

Part 3) There are no real solutions

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

If the radicand is positive

$(b^{2}-4ac) >0$ ------> There are two real solutions

If the radicand is zero

$(b^{2}-4ac) =0$ ------> There is one real solution

If the radicand is negative

$(b^{2}-4ac)$ ------> There are no real solutions

therefore

Part 1) The radicand is positive

so

There are two real solutions

Part 2) The radicand is equal to zero

so

There is one real solution

Part 3) The radicand is negative

so

There are no real solutions

7 0

3 years ago

Read 2 more answers