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MariettaO [177]
4 years ago
12

Find the dimensions of the box described.

Mathematics
1 answer:
Rina8888 [55]4 years ago
5 0

The dimensions of the box are 6 inches, 12 inches and 10 inches

Step-by-step explanation:

There is a box, with dimensions length, width and height

  • The length is twice as long as the width
  • The height is 4 inches greater than the width
  • The volume is 720 cubic inches

We need to find its dimensions

Assume that the width of the box is x

∵ The width of the box is x

∵ The length is twice as long as the width

- Twice means times 2

∴ The length of the box = 2(x) = 2x

∵ The height is 4 inches greater than the width

- 4 inches greater means add 4

∴ The height of the box = x + 4

∵ The volume of the box = length × width × height

∵ length = 2x , width = x , height = x + 4

∴ The volume of the box = (2x) × (x) × (x + 4)

∵ (2x) × (x) = 2x²

∵ 2x²(x + 4) = (2x²)(x) + (2x²)(4) = 2x³ + 8x²

∴ The volume of the box = 2x³ + 8x²

∵ The volume of the box is 720 inches³

∴ 2x³ + 8x = 720

- Subtract 720 from both sides

∴ 2x³ + 8x² - 720 = 0

- Use your calculator to solve the equation and find the value of x

∴ x = 6

∴ The width of the box = 6 inches

∴ The length of the box = 2(6) = 12 inches

∴ The height of the box = 6 + 4 = 10 inches

The dimensions of the box are 6 inches, 12 inches and 10 inches

Learn more:

You can learn more about volume in brainly.com/question/12497249

#LearnwithBrainly

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Step-by-step explanation:

For both problems, use the formula for surface area of a cylinder:

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<u>PROBLEM A</u>

"the cylinder is 60 cm long" is h = 60.

If given diameter, you can find "r" by dividing it by 2. d = 2r

Given d = 4, then r = 2.

SA = 2πr² + 2πrh

SA = 2π2² + 2π2(60)

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SA ≈ 779           Rounded answer

Remember to include the units.

The surface area is about 779 cm².

<u>PROBLEM B</u>

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Remember to include the units.

The surface area is about 1837 cm².

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