Prove:
Using mathemetical induction:
P(n) = 
for n=1
P(n) = 
= 6
It is divisible by 2 and 3
Now, for n=k, 
P(k) = 
Assuming P(k) is divisible by 2 and 3:
Now, for n=k+1:
P(k+1) = 
P(k+1) = 
P(k+1) = 
Since, we assumed that P(k) is divisible by 2 and 3, therefore, P(k+1) is also
divisible by 2 and 3.
Hence, by mathematical induction, P(n) = is divisible by 2 and 3 for all positive integer n.
Answer:
The sum of the probabilities is greater than 100%; and the distribution is too uniform to be a normal distribution.
Step-by-step explanation:
The sum of the probabilities of a distribution should be 100%. When you add the probabilities of this distribution together, you have
22+24+21+26+28 = 46+21+26+28 = 67+26+28 = 93+28 = 121
This is more than 100%, which is a flaw with the results.
A normal distribution is a bell-shaped distribution. Graphing the probabilities for this distribution, we would have a bar up to 22; a bar to 24; a bar to 21; a bar to 26; and bar to 28.
The bars would not create a bell-shaped curve; thus this is not a normal distribution.
Answer:
Dylan delivered 140 parcels on Wednesday.
Step-by-step explanation:
On Wednesday:
On Wednesday, he delivered x parcels.
Thursday:
10% more than Wednesday, so 100 + 10 = 110% of x = 1.1x
Friday:
50% pless than on Thursday, so 100 - 50 = 50% of 1.1x = 0.5*1.1*x.
THis is equals to 77. So
Dylan delivered 140 parcels on Wednesday.
Answer:
1 1/2 eggs
1/2 almond paste
1/8 vanilla
3/8 sugar
Step-by-step explanation:
