First, subtract px2 from both sides.
Now you have:
x3 - px2 = (1 - p) x1
Next, divide both sides by (1 - p)
So now you have
x3 - px2/(1 - p) = x1
...as your final answer
*You can decide if you want to leave the parenthesis in your final answer, I left them there so it could be visible where I put them. :)
<h2>
<u>Sol</u><u>ution</u><u>:</u></h2>
Equation: x² + 10x + 21
<u>Step</u><u> </u><u>1</u><u>:</u> Find two numbers that can add up to 10 and be multiplied to 21. We have: 7 & 3, in the sense that 7+3=10, and 7×3=21. Replacing 10 with 7+3, the equation is now → x² + 7x + 3x + 21
<u>Step</u><u> </u><u>2</u><u>:</u> Get the new equation bracketed → (x² + 7x) (+3x + 21)
<u>Step</u><u> </u><u>3</u><u>:</u> Use 'x' in the equation. For the first part, we have 'x'. x² = x × x so, bring out one x out side the bracket, divide 7x by = 7 → x (x +7). Do the same for the second part by dividing 21 by 3 = 7, and then bringing out 3 from the bracket → 3 (x + 7).
Bringing everything together, we have: x(x+7) +3(x+7) → (x+3) (x+7)
<h3>
<u>Final</u><u> </u><u>ans</u><u>wer</u><u>:</u></h3>
(x+3) (x+7)
<h3 />
Answer:
7.
Solution given;
male=15
female=27
1st term=5*3
2nd term=3*3*3
now
Highest common factor=3
So
<u>The</u><u> </u><u>maximum</u><u> </u><u>number</u><u> </u><u>of</u><u> </u><u>groups</u><u> </u><u>that</u><u> </u><u>the</u><u> </u><u>teacher</u><u> </u><u>can</u><u> </u><u>make</u><u> </u><u>is</u><u> </u><u>3</u><u>.</u>
<u>and</u><u> </u><u>each</u><u> </u><u>team</u><u> </u><u>contains</u><u> </u><u>5</u><u> </u><u>male and</u><u> </u><u>9</u><u> </u><u>female</u><u>.</u>
Change the fractions so they have common denominators. For example. If adding 4/8 + 2/3, a common denominator of the two could be 24. Change both fractions to have a denominator of 24. To do this:
(4/8)×(3/3)= 12/24
(2/3)×(8/8)=16/24
Now that both fractions have denominators of 24, you can simply add the numerators to get your answer. in this case, it would be 28/24
Answer:
10 feet
Step-by-step explanation:
BC = CD*tan(30 ) = 5
AC = CD*tan(60) = 15
=> AB = AC-BC = 10