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stira [4]
3 years ago
10

If sin^2(x) - 2sin(x) = 2, then sin(x) = _____.

Mathematics
1 answer:
alekssr [168]3 years ago
3 0
Let z = sin(x).
.. z^2 -2z = 2
.. z^2 -2z +1 = 3
.. (z -1)² = 3
.. z -1 = ±√3
.. z = 1 -√3 . . . . . the positive solution is extraneous

sin(x) = 1 -√3
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Solve the equation below for x. -1 2(3x - 4) = 11
Lesechka [4]

Answer:

x= 37/36

Step-by-step explanation:

−12(3x−4)=11

Step 1: Simplify both sides of the equation.

−12(3x−4)=11

(−12)(3x)+(−12)(−4)=11(Distribute)

−36x+48=11

Step 2: Subtract 48 from both sides.

−36x+48−48=11−48

−36x=−37

Step 3: Divide both sides by -36.

−36x

−36

=

−37

−36

x=

37

36

Answer:

x=

37

36

8 0
3 years ago
Read 2 more answers
A bag of marbles has 6 red marbles and 7 green marbles in it. What is the percent probability of pulling a green marble out of t
soldi70 [24.7K]

Answer:

If a bag contains 4 red marbles, 3 blue marbles, and 7 green marbles and a marble is randomly selected from the bag, what is the probability that it is blue? P=3/(3+4+7)=3/14 because each of 14 marbles is equally likely to be drawn.

Step-by-step explanation:

7 0
3 years ago
What is tan angle QTR if line PR is tangent to circle T at Q, and TS = 1 cm?
lions [1.4K]
Tangent = opposite / adjacent

In the diagram:
TQ is the short leg or the opposite
QR is the long leg or the adjacent
TR is the hypotenuse. TS is part of the hypotenuse.

Tan(QTR) = TQ / QR

TS = 1 ; TQ = TS  so, TQ = 1

Tan(QTR) = 1/QR

I think the answer is C.RQ
3 0
3 years ago
A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by V = x2h
creativ13 [48]

It is given in the question that

A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by

V = x^2h cm^3

And the edge length of the base is 12 cm, the edge length of the base is decreasing at a rate of 2 cm/min, the height of the box is 6 cm, and the height is increasing at a rate of 1 cm/min.

Here we differentiate V with respect to t, and we use product rule, that is

V = 2xh(dx/dt)+ x^2(dh/dt)

Substituting the given values , we will get

[tex]dV/dt = 2(12)(6)(-2)+ 12^2(1)[/tex]

dV/dt = -288+144 = -144cm^3/min

So at that moment, the volume is decreasing at the rate of

144 cm^3/min

4 0
3 years ago
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a certain number of yams is sufficient to feed 20 students for 12 days for how many days would the same number of yams feed 15 s
Softa [21]

Step-by-step explanation:

no of days = (15×12)/20= 9 days

I hope this helps

6 0
3 years ago
Read 2 more answers
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