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3 years ago

Do it nowhhahahhaahgcgftyuoihgcfhygfcghj

Mathematics

2 answers:

alina1380 [7]3 years ago

7 0

Answer: 6+10b

Step-by-step explanation: Subtract 1 and 2 from 9, and you will end up with 6. 3b and 7b is 10b when added together. I hope this helps. Have a nice day.

bazaltina [42]3 years ago

6 0

The 3rd one because you need to use the formula and calculate

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What is the horizontal distance between (−5/3, -2) and (4, -2)?

Nataly [62]

Answer:

-2?

Step-by-step explanation:

use y2-y1 over x2-x1 to find the answer. So you would do -2--5/3 over 4--2. The two negitives turn into a positive. SO it is now -2+5/3 over 4+2. -2+5/3= -1/3 over 4+2=6 it is now -1/3/6 which equals -2. So I think the answer is -2.<u> I do not know if you should trust me on this but I tried. </u>

6 0

3 years ago

39,892 to the nearest 1000 on the number line

Iteru [2.4K]

I'm pretty sure it would be 40,000 because if i'm not mistaken you meant the nearest 10,000 since the number is 39,892.

7 0

3 years ago

The animal shelter requires 1 pound of food for every 3 animals. This directly proportional relationship is represented by the e

fomenos

Answer:

graph B or the second graph

Step-by-step explanation:

4 0

4 years ago

Fill in the blanks. Suppose the probability at a light bulb factory of a bulb being defective is 0.11. If a shipment of 133 bulb

anastassius [24]

Answer:

The number of defective bulbs in the shipment should be around 15, give or take 4.

Step-by-step explanation:

For each bulb, there are only two possible outcomes. Either it is defective, or it is not. The probability of a bulb being defective is independent of any other bulb. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Suppose the probability at a light bulb factory of a bulb being defective is 0.11

This means that $p = 0.11$

Shipment of 133 bulbs:

This means that $n = 133$

Mean and standard deviation:

$E(X) = np = 133*0.11 = 14.63$

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{133*0.11*0.89} = 3.61$

Rounding to the nearest integers:

The number of defective bulbs in the shipment should be around 15, give or take 4.

8 0

3 years ago

Two balls are drawn in succession out of a box containing

victus00 [196]

There are a total of 8 balls

The probability of drawing a white ball is 4/8 on the first draw.
If you replace the ball then the probability will still be 4/8 for a white ball, since these events are independent of each other you multiply 4/8 x 4/8 = 16/64 or 1/4 then the probability of drawing at least 1 red ball with replacement is 1 - 1/4 = 3/4

Now without replacement:
the probability of drawing a white ball is 4/8 since you don't replace the ball then the probability of drawing a white ball the second time is 3/7 again multiply these two probabilities: 4/8 x 3/7 = 12/56 the the probability of drawing at least 1 red ball is 1- 12/56 = 44/56 or 11/14

4 0

3 years ago