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3 years ago

Point S is between R and T. If RS = 2x + 10, ST = x - 4, and RT = 4x - 10, find

Mathematics

1 answer:

Alborosie3 years ago

8 0

Answer:

i dont really get your question tho

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What is the surface area of a cylinder with base radius 4 and height 5

mestny [16]

A=226.19 A=2πrh+2πr2=2·π·4·5+2·π·42≈226.19467

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3 years ago

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Vlada [557]

The equation of the line f(x) slope 3

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2 years ago

Write the general polynomial p(x) if its only zeros are 1 4 and -3 with multiplicites 3 2 and 1 respectively what is the degree

kompoz [17]

Answer:

The 6th degree polynomial is $p(x) = (x-1)^3(x-4)^2(x+3)$

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots $x_{1}, x_{2}, x_{n}$ such that it can be written as: $a(x - x_{1})*(x - x_{2})*...*(x-x_n)$ , in which a is the leading coefficient.

Zero 1 with multiplicity 3.

$p(x) = (x-1)^3$

Zero 4 with multiplicity 2.

Considering also the zero 1 with multiplicity 3.

$p(x) = (x-1)^3(x-4)^2$

Zero -3 with multiplicity 1:

Considering the previous zeros:

$p(x) = (x-1)^3(x-4)^2(x-(-3)) = (x-1)^3(x-4)^2(x+3)$

Degree is the multiplication of the multiplicities of the zeros. So

3*2*1 = 6

The 6th degree polynomial is $p(x) = (x-1)^3(x-4)^2(x+3)$

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3 years ago

Two student share 3 granola bars equally. How many granola bars does eachstudent get?

Murrr4er [49]

1 and they split the other in half

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3 years ago

Read 2 more answers

3x^2 + 64 = 2x^2/2 find the roots of the quadratic equation

Reil [10]

Answer:

4√2i , -4√2i.

Step-by-step explanation:

3x^2 + 64 = 2x^2/2

3x^2 + 64 = x^2

2x^2 + 64 = 0

2x^2 = -64

x^2 = -32

x = +/- √-32

x = +/- √16* -2

x = +/- 4√2 i.

8 0

4 years ago