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Korvikt [17]
2 years ago
10

An angle measures 62.8° less than the measure of its supplementary angle. What is the measure of each angle?

Mathematics
1 answer:
amm18122 years ago
7 0
Angle 1
=180-62.8
=117.2

Angle 2
=180-117.2
=62.8
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Many credit card companies charge a compound interest rate of 1.8% per month on a credit card balance. Nelson owes $850 on a cre
Finger [1]

The sequence will be


850, 850 \times (1.018)^1, 850 \times (1.018)^2, 850 \times (1.018)^3, 850 \times (1.018)^4, ...


That's


850, 865.30, 880.875, 896.731, 912.872, ...



8 0
3 years ago
Read 2 more answers
How could you find 3/8% of 800
Damm [24]
Well 3/8 is .375 but times 100 is 37.5%
Then 37.5% of 800 is 300
7 0
2 years ago
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Please Answer Soon!
Andru [333]

Answer:

sorry for getting it wrong

7 0
2 years ago
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Given that a function, h, has a domain of -3 ≤ x ≤ 11 and a range of 1 ≤ h(x) ≤ 25 and that h(8) = 19 and h(-2) = 2, select the
morpeh [17]

Answer:

Option D. h(2) = 16

Step-by-step explanation:

Verify each statement

case A) h(8) = 21

The statement is false

Because

we know that

h(8)=19 -----> given value

and

If h(8) = 21  then f(x) is not a function

case B) h(13) = 18

The statement is false

Because x=13 not belong to the domain of the function

case C) h(-3) = -1

The statement is false

Because

x=-3 belong to the domain

but

h(-3)=-1   not belong to the range of the function

case D) h(2) = 16

The statement could be true

Because

x=2 ----> belong to the domain of the function

h(2)=16 ----> belong to the range of the function

5 0
3 years ago
What would be the coordinates of triangle A'B'C' if triangle ABC was dilated by a factor of
notsponge [240]

Answer:

A(0,0)\rightarrow A'(0,0) \\ B(2,0)\rightarrow B'(\frac{2}{3},0) \\ C(0,2)\rightarrow C'(0,\frac{2}{3})

Step-by-step explanation:

The question is as following:

The verticies of a triangle on the coordinate plane are

A(0, 0), B(2, 0) and C(0, 2).

What would be the coordinates of triangle A'B'C' if triangle ABC was dilated by a factor of 1/3 ?

=============================================

Given: the vertices of a triangle ABC are A(0, 0), B(2, 0) and C(0, 2).

IF the triangle is dilated by a factor of k about the origin, then

(x,y) → (kx , ky)

that triangle ABC was dilated by a factor of 1/3 to create the triangle A'B'C'.

It is given that triangle ABC was dilated by a factor of 1/3 to create the triangle A'B'C'.

If a figure dilated by a factor of 1/3 about the origin

So, (x,y)\rightarrow (\frac{1}{3}x,\frac{1}{3}y)

<u>So, The coordinates of the triangle A'B'C' are:</u>

A(0,0)\rightarrow A'(0,0) \\ B(2,0)\rightarrow B'(\frac{2}{3},0) \\ C(0,2)\rightarrow C'(0,\frac{2}{3})

6 0
2 years ago
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