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NikAS [45]
3 years ago
10

What is the value of x? please hurry.

Mathematics
1 answer:
Artist 52 [7]3 years ago
4 0

Answer:

8

Step-by-step explanation:

Use the pythagorean theorem. The hypotenuse (c) is 10, and one of the sides, let's say (b), is 6. Therefore, we need to solve for a and plug and chug. Let's do that:

c^2 = a^2+b^2

a = \sqrt{c^2-b^2}

Now let's plug in what we know:

a = \sqrt{10^2-6^2} = \sqrt{64} = 8

Therefore, a = x = 8

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Write an equation in slope-intercept from the line with slope 3/5 and y-intercept 1 . Then graph the line.
never [62]

Answer:

y=(3/5)x+1

Step-by-step explanation:

Slope-intercept form of a line is as follows

y=mx+c, where m is the slope of the line and c is the y intercept.

Hence the equation of the line is y=(3/5)x+1

3 0
3 years ago
David bought a car for 5000$ for how much should he sell it if he wants 10% profit from it
BartSMP [9]

Answer:

Step-by-step explanation:

5,500$ lol

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3 years ago
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Steven wants to keep track of how many miles he walks in a year. He expects to walk 5 miles per day, and he has
WINSTONCH [101]

Answer:

The fourth choice.

Step-by-step explanation:

Because since 90 miles is basically counted as your first day, you do the number of days, n, minus 1 and then multiply it by 5 to find the number of miles walked after the first day. Then you add it to 90.

6 0
3 years ago
A lamina with constant density rho(x, y) = rho occupies the given region. Find the moments of inertia Ix and Iy and the radii of
jenyasd209 [6]

Answer:

Ix = Iy = \frac{ρπR^{4} }{16}

Radius of gyration x = y =  \frac{R}{4}

Step-by-step explanation:

Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.

Mass of disk = ρπR2

Moment of inertia about its perpendicular axis is \frac{MR^{2} }{2}. Moment of inertia of quarter disk about its perpendicular is \frac{MR^{2} }{8}.

Now using perpendicular axis theorem, Ix = Iy = \frac{MR^{2} }{16} = \frac{ρπR^{4} }{16}.

For Radius of gyration K, equate MK2 = MR2/16, K= R/4.

3 0
3 years ago
During a period of 30 working days, Deborah was late 80% of the time. How many days was she late?
erik [133]
Fairly straightforward question. She works 30 days and is late 80% or 0.8
We can model our equation
Num days late = late percentage * num working days
Basically fine portion of working days that she was late.

Num days late = 0.8 * 30=24

So Deborah was late 24 out of 30 working days. Would appreciate a brainliest
8 0
2 years ago
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