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PilotLPTM [1.2K]
3 years ago
13

What is the inverse of the given relation y = 7x² ?

Mathematics
1 answer:
beks73 [17]3 years ago
7 0

Answer:

y = square root(x/7)

Step-by-step explanation:

switch x and y

x = 7y^2

solve for y

x/7 = y^2

square root(x/7) =y

y inverse is

y= square root(x/7)

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((W to the power of 2)) to the power of 4
UkoKoshka [18]
X^2^4 = x^8

Just multiply then 2 and 4 to get 8
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Step-by-step explanation:

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2 years ago
What is the common difference in the following arithmetic sequence?<br> 2.8, 4.4, 6, 7.6
Volgvan

Answer:

1.6

Step-by-step explanation:

4.4 - 2.8 = 1.6

6 - 4.4 = 1.6

7.6 - 6 = 1.6

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3 years ago
Choose all that give the correct expression for the quantity described. The difference of nine times a number x and the quotient
ohaa [14]

Step-by-step explanation:

We are to get the expression for the following statements;

1) The difference of nine times a number x and the quotient of that number and 5.

The product of nine and a number x is expressed as;

=9 \times x\\= 9x

The quotient of that number and 5.

= \frac{x}{5}

The difference between both expression;

9x - \frac{x}{5}

Hence, the difference of nine times a number x and the quotient of that number and 5 is expressed as 9x - \frac{x}{5}

2) Eight more than the quotient of twelve and a number n

Quotient of twelve and a number n is expressed as:

\frac{n}{12}

Eight more than the resulting function is;

\frac{n}{12}+8

Hence eight more than the quotient of twelve and a number n is expressed as \frac{n}{12}+8

3) The product of a number and the quantity 'six minus the number' plus the quotient of eight and the number.

Let the number be x:

six minus the number is expressed as;

6-x

product of a number x and the quantity 'six minus the number is;

x(6-x)

quotient of eight and the number is;

\frac{8}{x}

Taking the resulting sum of the last two expression

x(6-x) + 8x

Hence the product of a number and the quantity 'six minus the number' plus the quotient of eight and the number is expressed as;

x(6-x) + 8x

4) Sum of three consecutive even integers. 2x + (2x + 2) + (2x + 4).

Let the first even number be 2x

The consecutive even numbers are gotten by adding 2 to the preceding number. The two consecutive even integers are 2x+2 and 2x+2+2

the sum of three consecutive even integers is expressed as;

= 2x +(2x+2)+(2x+2+2)\\=  2x+(2x+2)+(2x+4)

4 0
3 years ago
Which expression represents the sum (3z−11)+(6−6z) ?
Fudgin [204]

Answer: z = -5/-3

Step-by-step explanation:

(3z−11)+(6−6z)

3z - 11 + 6 - 6z

- 6z + 3z - 11 + 6

- 3z - 5

z = -5/-3

6 0
3 years ago
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