The position of an open-water swimmer is shown in the graph. The shortest route to the shoreline is one that is perpendicular to
1 answer:
Answer:
An equation that represents this path is described below in detail.
Step-by-step explanation:
The equalization that describes the pathway of the swimmer to the shoreline can be described in the slope-intercept pattern, given as.
Where,
Slope (m) = the adverse reciprocal of the incline of the shoreline, considering it is perpendicular to it = ??
y-intercept (b) = ??
Find the incline of the shoreline using, (0, 1) and (4, 4):
.
Considering the incline of the shoreline is ¾. The incline of the pathway of the swimmer would be the adverse reciprocal of ¾.
The adverse reciprocal of ¾ = -⁴/3.
The incline of the swimmer's path = -⁴/3.
Applying the coordinate of the position of the swimmer (6, 1), and the incline of the way, we can find b, the y-intercept of the way.
Substitute x = 6, y = 1 and m = -⁴/3 into y = mx + b, to find b.
Thus:
1 = (-⁴/3)(6) + b
1 = -8 + b
Add 8 to both sides
1 + 8 = b
9 = b
b = 9
Substitute m = -⁴/3 and b = 9 into y = mx + b.
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Answer:
C.
General Formulas and Concepts:
<u>Calculus</u>
- Mean Value Theorem (MVT) - If f is continuous on interval [a, b], then there is a c∈[a, b] such that
- MVT is also Average Value
Step-by-step explanation:
<u>Step 1: Define</u>
f'(c) = 20
Interval [1, b]
<u>Step 2: Check/Identify</u>
Function [1, b] is continuous.
Derivative [1, b] is continuous.
∴ There exists a c∈[1, b] such that
<u>Step 3: Mean Value Theorem</u>
- Substitute:
- Rewrite:
And we have our final answer!