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Advocard [28]
2 years ago
11

M+(7-9)/n when m =2.5 and n =5 i need the answer fast plz ✨

Mathematics
2 answers:
Kobotan [32]2 years ago
3 0

Answer:0.1

Step-by-step explanation:

Substract ,add & divide

bekas [8.4K]2 years ago
3 0

Answer:

2.5 + (7 - 9) = (2.5 - 2) \div 5 = 0.5 \div 5  = 0.1

Step-by-step explanation:

无脑代入求值7-9=-2移除括号变号

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Solve 3(x +15) ≤5(x+2) + 15<br>​
belka [17]

Answer:

x≥5

Step-by-step explanation:

3(x+15)≤5(x+2)+15

3x+45≤5x+10+15

3x+35≤5x+25

3x-5x≤25-35

-2x≤-10

x≥5

{x:xEx:6,7,8,9,10....}

Hope this helps ;) ❤❤❤

3 0
3 years ago
Can someone plz tell me the answer quick!!
patriot [66]
He worked 9 hours in his first job and 5 hours in his second
5 0
3 years ago
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28 is what precent of 50
WITCHER [35]

Answer:

56%

Step-by-step explanation:

28/50=56/100

7 0
3 years ago
Read 2 more answers
Show 2 different solutions to the task.
laila [671]

Answer with Step-by-step explanation:

1. We are given that an expression n^2+n

We have to prove that this expression is always is even for every integer.

There are two cases

1.n is odd integer

2.n is even integer

1.n is an odd positive integer

n square is also odd integer and n is odd .The sum of two odd integers is always even.

When is negative odd integer then n square is positive odd integer and n is negative odd integer.We know that difference of two odd integers is always even integer.Therefore, given expression is always even .

2.When n is even positive integer

Then n square is always positive even integer and n is positive integer .The sum of two even integers is always even.Hence, given expression is always even when n is even positive integer.

When n is negative even integer

n square is always positive even integer and n is even negative integer .The difference of two even integers is always even integer.

Hence, the given expression is always even for every integer.

2.By mathematical induction

Suppose n=1 then n= substituting in the given expression

1+1=2 =Even integer

Hence, it is true for n=1

Suppose it is true for n=k

then k^2+k is even integer

We shall prove that it is true for n=k+1

(k+1)^1+k+1

=k^1+2k+1+k+1

=k^2+k+2k+2

=Even +2(k+1)[/tex] because k^2+k is even

=Sum is even because sum even numbers is also even

Hence, the given expression is always even for every integer n.

3 0
3 years ago
Kieth bought 165 crayons that came in packs of 15. There were 9 colors of crayons how many packs of crayons did Kieth buy?
Andrej [43]

Answer:

11 packs

Step-by-step explanation:

165/15 = 11

6 0
3 years ago
Read 2 more answers
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