Answer:
It can go 250 m deep
Step-by-step explanation:
Answer:
We assume, that the number 180 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 100% equals 180, so we can write it down as 100%=180.
4. We know, that x% equals 483.6 of the output value, so we can write it down as x%=483.6.
5. Now we have two simple equations:
1) 100%=180
2) x%=483.6
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
100%/x%=180/483.6
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for 483.6 is what percent of 180
100%/x%=180/483.6
(100/x)*x=(180/483.6)*x - we multiply both sides of the equation by x
100=0.37220843672457*x - we divide both sides of the equation by (0.37220843672457) to get x
100/0.37220843672457=x
268.66666666667=x
x=268.66666666667
now we have:
483.6 is 268.66666666667% of 180
Answer:
The answer is 1
Step-by-step explanation:
Answer:
x=5
Step-by-step explanation:
4x+10=30
-10 -10 on both sides
4x=20
Divide 4 on both sides
20/4=5
✨Hope this helps!!✨
For polar form you need to find the modulus (length of the vector) and the argument (angle of the vector) and present in form rcis(Arg) or re^Argi
start with the modulus r=sqrt(a^2 +b^2)
=sqrt(-2^2 +2^2)
= sqrt(4+4)
=sqrt(8)
=2sqrt(2)
next the argument, firstly arg=tan(b/a)
= tan(2/2)
=tan(1)
=pi/4 . (exact values table)
Now consider the quadrant the complex number is in, as it is (-2,2) it is in the second quadrant and as such your Arg value is:
Arg=pi-arg
= pi-pi/4
= 3pi/4
add it all together and your complex number in polar form is:
2sqrt2cis(3pi/4)
note: cis is short hand for cos(x)+isin(x), it is possible your tutor would rather you use the complex exponential form which is simply re^Argi and your answer would look like:
2sqrt2e^(3pi/4)i
Also notice the difference between arg and Arg as this often slips students up and always present Arg in prinicple argument form ie -pi<Arg<pi
Hopefully this has been clear enough and good luck