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kumpel [21]
3 years ago
9

Which expression is equivalent to x + x + 4y?

Mathematics
1 answer:
Harrizon [31]3 years ago
5 0

Answer:

2x + 4y , There are many more "equivalent" expressions such as 1x+1x+4(y) or 2(x)+4(y).

Step-by-step explanation:

Combine like terms for the 2 "x".

x+x+4y=2x+4y

That is your most simplified expression.

2x + 4y

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Carly tutors students in math on the weekends and offers both thirty-minute sessions and sixty-minute sessions. She earns $15 fo
creativ13 [48]

Answer:

(15*x)+((25)(x-2))=230 THE ANSWER D. X=7

I GOT IT CORRECT

Step-by-step explanation:

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3 years ago
BRAINLIESTT ASAP! PLEASE HELP ME :)
Anvisha [2.4K]

Step-by-step explanation:

\displaystyle y = Asec(Bx - C) + D

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\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{4} = 0 \\ Period → \frac{2}{4}π = \frac{π}{2}

Therefore we have our answer.

Extended Information on the trigonometric function

\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|

NOTE: Sometimes, your <em>vertical shift</em> might tell you to shift your graph below or above the <em>midline</em> where the amplitude is. Moreover, ALL <em>tangent</em>,<em> </em><em>secant</em>, <em>cosecant</em>, and <em>cotangent</em> functions have NO AMPLITUDE.

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3 0
3 years ago
Solve f(x)= (x - 1(- 5)?
Masja [62]

Answer:

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Step-by-step explanation:

6 0
2 years ago
Lauren's scores on her math tests are, 93, 91, 98, 100, 95, 92 , and 96. What score could Lauren get on he next math test so tha
Ugo [173]
First you need to find the mean & median:
mean:
93 + 91 + 98 + 100 + 95 + 92 + 96 = 665
665 / 7 = 95
median:
<u>91</u>, <em>92</em>, <u>93</u>, 95, <u>96</u>, <em>98</em>, <u>100</u>
95

Because the mean and median are the same, her next test score should be 95. The average of the current average and 95 (her next test score) is 95, so that will remain the same. If you add 95 to the median list,the median will still be 95. The same goes for the mean.Her next test score should be 95.
7 0
2 years ago
The market and Stock J have the following probability distributions:
denis-greek [22]

Answer:

1) E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

2) E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

3) E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

4) E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

Step-by-step explanation:

For this case we have the following distributions given:

Probability  M   J

0.3           14%  22%

0.4           10%    4%

0.3           19%    12%

Part 1

The expected value is given by this formula:

E(X)=\sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

Part 2

E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

Part 3

We can calculate the second moment first with the following formula:

E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

Part 4

We can calculate the second moment first with the following formula:

E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

8 0
3 years ago
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