See the attached figure to better understand the problem
we know that
tan 29°=AC/CB--------> CB=AC/tan 29°
AC=110 ft
CB--------> <span>how far the man is from the helicopter landing pad
</span>so
CB=AC/tan 29°----------> CB=110/ tan 29°----------> CB=198.45 ft
the answer is
the man is 198.45 ft from the helicopter landing pad
Answer:
2,5
Step-by-step explanation:
2 to the right and 5 up
The answer is 7 feet becaise 0 opp ik
I think your answer would be C.