Answer:
The percent of callers are 37.21 who are on hold.
Step-by-step explanation:
Given:
A normally distributed data.
Mean of the data,
= 5.5 mins
Standard deviation,
= 0.4 mins
We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.
Lets find z-score on each raw score.
⇒
...raw score,
=
⇒ Plugging the values.
⇒
⇒
For raw score 5.5 the z score is.
⇒
⇒
Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.
We have to work with P(5.4<z<5.8).
⇒ 
⇒ 
⇒
⇒
and
.<em>..from z -score table.</em>
⇒ 
⇒
To find the percentage we have to multiply with 100.
⇒ 
⇒
%
The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21
18 because they need to be identical and you only have 18 chocolate bars
Answer: (b)
Step-by-step explanation:
Given
The letter "BHUTAN" has to be arranged
For filing the first place of 6 letter word, we have 6 choices
Similarly for filling the second place of the word, we have 5 choices as 1 letter is already filled.
In this way, the remaining places can be filled in 4, 3, 2, and 1 way
On combining the above, 6 places can be filled in

Thus, option (b) is correct.
Answer:
0.75
Step-by-step explanation:
Step-by-step explanation: So ig this wat you ASKED FOR?