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sp2606 [1]
3 years ago
8

4 more than 4 times x is 45

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
6 0
The answers is 4+4*x=45
balu736 [363]3 years ago
3 0
4 more than 4 times x is 45 the answer will be x=41/4
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If 541 people use the swimming pool and children pay 1.75 dollars and adults pay 2.25 and in total earned was 1041.25 how many c
Zina [86]

Answer:

352 children

Step-by-step explanation:

Solve algebraically using a system of equations

Assign variables

let "a" be the number of adults

let "c" be the number of children    <-- We want to find this

a + c = 541             Equation for number of people

2.25a + 1.75c = 1041.25           Equation for money

<u>Rearrange the equation for people</u>. Isolate the variable you don't want to find.

a = 541 - c

<u>Substitute</u> "541 - c", replacing "a", in the equation for money

2.25a + 1.75c = 1041.25              

2.25(541 - c) + 1.75c = 1041.25               Distribute over brackets

1217.25 - 2.25c + 1.75c = 1041.25               Collect like terms

1217.25 - 0.5c = 1041.25                   Simplified equation

<u>Start isolating "c".</u> Move anything that's not "c" to the right side. Move numbers in reverse BEDMAS order. That means we will add/subtract before dividng/multiplying. When moving a number, do its reverse operation to the entire equation.

1217.25 - 0.5c = 1041.25      Do the reverse of positive 1217.25

1217.25 - 1217.25 - 0.5c = 1041.25 - 1217.25    Subtract 1217.25 on both sides  

-0.5c = -176               Do the reverse of multiplying by -0.5

-0.5c/-0.5 = -176/-0.5               Divide both sides by -0.5

c = 352                Number of children

Therefore, there were 352 children in the pool.

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Step-by-step explanation:

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So, I came up with something like this. I didn't find the final equation algebraically, but simply "figured it out". And I'm not sure how much "correct" this solution is, but it seems to work.

f(x)=\sin(\omega(x))\\\\f(\pi^n)=\sin(\omega(\pi^n))=0, n\in\mathbb{N}\\\\\\\sin x=0 \implies x=k\pi,k\in\mathbb{Z}\\\Downarrow\\\omega(\pi^n)=k\pi\\\\\boxed{\omega(x)=k\sqrt[\log_{\pi} x]{x},k\in\mathbb{Z}}

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Ga college readiness mathematics
igomit [66]
What is the question?????
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Rudik [331]

Answer:

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A function has only one output value for each input value.

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