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sp2606 [1]
3 years ago
8

4 more than 4 times x is 45

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
6 0
The answers is 4+4*x=45
balu736 [363]3 years ago
3 0
4 more than 4 times x is 45 the answer will be x=41/4
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A total of 12 players consisting 6 male and 6 female badminton players are attending a training camp
abruzzese [7]

Step-by-step explanation:

<em>"A total of 12 players consisting 6 male and 6 female badminton players are attending a training camp."</em>

<em />

<em>"(a) During a morning activity of the camp, these 12 players have to randomly group into six pairs of two players each."</em>

<em>"(i) Find the total number of possible ways that these six pairs can be formed."</em>

The order doesn't matter (AB is the same as BA), so use combinations.

For the first pair, there are ₁₂C₂ ways to choose 2 people from 12.

For the second pair, there are ₁₀C₂ ways to choose 2 people from 10.

So on and so forth.  The total number of combinations is:

₁₂C₂ × ₁₀C₂ × ₈C₂ × ₆C₂ × ₄C₂ × ₂C₂

= 66 × 45 × 28 × 15 × 6 × 1

= 7,484,400

<em>"(ii) Find the probability that each pair contains players of the same gender only. Correct your final answer to 4 decimal places."</em>

We need to find the number of ways that 6 boys can be grouped into 3 pairs.  Using the same logic as before:

₆C₂ × ₄C₂ × ₂C₂

= 15 × 6 × 1

= 90

There are 90 ways that 6 boys can be grouped into 3 pairs, which means there's also 90 ways that 6 girls can be grouped into 3 pairs.  So the probability is:

90 × 90 / 7,484,400

= 1 / 924

≈ 0.0011

<em>"(b) During an afternoon activity of the camp, 6 players are randomly selected and 6 one-on-one matches with the coach are to be scheduled.</em>

<em>(i) How many different schedules are possible?"</em>

There are ₁₂C₆ ways that 6 players can be selected from 12.  From there, each possible schedule has a different order of players, so we need to use permutations.

There are 6 options for the first match.  After that, there are 5 options for the second match.  Then 4 options for the third match.  So on and so forth.  So the number of permutations is 6!.

The total number of possible schedules is:

₁₂C₆ × 6!

= 924 × 720

= 665,280

<em>"(ii) Find the probability that the number of selected male players is higher than that of female players given that at most 4 females were selected. Correct your final answer to 4 decimal places."</em>

If at most 4 girls are selected, that means there's either 0, 1, 2, 3, or 4 girls.

If 0 girls are selected, the number of combinations is:

₆C₆ × ₆C₀ = 1 × 1 = 1

If 1 girl is selected, the number of combinations is:

₆C₅ × ₆C₁ = 6 × 6 = 36

If 2 girls are selected, the number of combinations is:

₆C₄ × ₆C₂ = 15 × 15 = 225

If 3 girls are selected, the number of combinations is:

₆C₃ × ₆C₃ = 20 × 20 = 400

If 4 girls are selected, the number of combinations is:

₆C₂ × ₆C₄ = 15 × 15 = 225

The probability that there are more boys than girls is:

(1 + 36 + 225) / (1 + 36 + 225 + 400 + 225)

= 262 / 887

≈ 0.2954

7 0
2 years ago
Wouldn't this be true ?
Lana71 [14]
I think this is true
4 0
3 years ago
Read 2 more answers
Carl and Tamera want to compare their tests in math class. They have taken six tests. Should they use the mean, median or mode t
Roman55 [17]

Answer:

Mean

Step-by-step explanation:

I said mean because it would allow both Carl and Tamera to average their scores and compare one side by side rather than comparing 6 each which would just be time consuming and it seems like it wouldn't be any other choices.

7 0
2 years ago
Evaluate and write as an integer<br><br> (-6)^2
IceJOKER [234]

Answer:

36

Step-by-step explanation:

(-6)² = (-6) × (-6)

= +36

8 0
2 years ago
Write the number in expanded form 68,020
allochka39001 [22]

Standard Form:

68,020

Expanded Notation Form:

 68,020 =

 60,000  

+ 8,000  

+ 0  

+ 20  

+ 0  

Expanded Factors Form:

   68,020 =

 6 × 10,000  

+ 8 × 1,000  

+ 0 × 100  

+ 2 × 10  

+ 0 × 1  

Expanded Exponential Form:

 68,020 =

       6 × 10^4

+ 8 × 10^3

+ 0 × 10^2

+ 2 × 10^1

+ 0 × 10^0

Word Form:

68,020 =

sixty-eight thousand twenty

4 0
2 years ago
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