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3 years ago

Which is greater... -8 , -18, 3, -19??

Mathematics

2 answers:

andrew-mc [135]3 years ago

7 0

It is 3 I hope this helps you

MrRissso [65]3 years ago

3 0

It is -3. A less negative number is greater while the more negative it is makes it smaller

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Explain why animals can hear sounds humans can't

DedPeter [7]

Better hearing and better sound censory

i think anyways

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3 years ago

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Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago

76. Currently, your savings for each month is capped at $400. If you start investing all of this into a savings plan earning 1%

Alexxandr [17]

Answer:

10 years and 10 months.

Step-by-step explanation:

The annually interest rate (ia) can be converted by monthly (im) by the equation:

(1 + im)¹² = 1 + ia

(1 + im)¹² = 1 +0.01

(1 + im)¹² = 1.001 (putting ln in both sides)

ln(1 + im)¹² = ln1.001

12*ln(1 + im) = 1.0x10⁻³

ln(1 + im) = 8.33x10⁻⁵(applying "e in both sides)

$e^{ln(1 + im)} = e^{8.33x10^{-5}}$

1 + im = 1.00083

im = 0.00083 = 0.083%

For a investimenting, the final amount (A) can be calculated by:

$A = R*(\frac{(1+i)^n-1}{i} )$

Where R is the amount invested per month, i is the interest, and n the number of months:

160000 = 400 * $\frac{(1 +0.00083)^n - 1}{0.00083}$

$\frac{(1 +0.00083)^n - 1}{0.00083}$ = 400

1.00083ⁿ - 1 = 0.332

1.00083ⁿ = 1.332 (applying ln in both sides)

n*ln1.00083 = ln1.332

8.3x10⁻⁴n = 0.2867

n = 345.4 months

345.4 months *1 yea12 months = 10 years and 10 months.

7 0

3 years ago

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Solve #14 for x and y plsss I WILL GIVE BRAINLY

frez [133]

7x - 44 = 4x + 4

Add both sides 44

7x - 44 + 44 = 4x + 4 + 44

7x = 4x + 48

Subtract both sides 4x

7x - 4x = 4x - 4x + 48

3x = 48

Divide both sides by 3

3x ÷ 3 = 48 ÷ 3

______________________________

Suppose that the angle between 39 and 4x + 4 is t degrees as you know they make a straight line together thus :

39 + t + 4x + 4 = 180

39 + t + 4(16) + 4 = 180

39 + t + 64 + 4 = 180

39 + t + 68 = 180

t + 107 = 180

Subtract both sides 107

t + 107 - 107 = 180 - 107

_____________________________

8y - 43 = 4x + 4 + t

8y - 43 = 4(16) + 4 + 73

8y - 43 = 64 + 4 + 73

8y - 43 = 68 + 73

8y - 43 = 141

Add both sides 43

8y - 43 + 43 = 141 + 43

8y = 184

Divide both sides by 8

8y ÷ 8 = 184 ÷ 8

6 0

3 years ago

Can 7 13 and 20 Make a triangle

Nadya [2.5K]

Answer:

yes

Step-by-step explanation:

i gussed

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3 years ago

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