"In Grade 2 and early in Grade 3, students learned to use bar models to solve two-step problems involving addition and subtraction. This is extended in this chapter to include multiplication and division.
<span>Both multiplication and division are based on the concept of equal groups, or the part-part-whole concept, where each equal group is one part of the whole. In Grade 2, students showed this with one long bar (the whole) divided up into equal-sized parts, or units. This unitary bar model represents situations such as basket of apples being grouped equally into bags." </span>https://www.sophia.org/tutorials/math-in-focus-chapter-9-bar-modeling-with-multipli
Answer:
option (c) 475
Step-by-step explanation:
let the automobile installment credit be 'C'
Given:.
Automobile installment credit accounted for 36 percent of all outstanding consumer installment credit
Now,
57 billion is 
of automobile installment credit
or
57 billion = × C
or
C = 57 × 3
or
C = 171 billion
now,
installment credit accounted = 36% of all outstanding consumer installment credit
or
171 billion = 0.36 × all outstanding consumer installment credit
or
All outstanding consumer installment credit = $475 billion
Hence, the correct answer is option (c) 475
Since you did not attach any picture we cannot say for sure what is the correct answer, but we can discuss the options in order to find the most probable correct answer.
First of all, according to the Cavalieri's principle, an oblique cylinder has the same volume as a right cylinder with the same base surface area and same height.
A cross-section of an oblique cylinder will be a small right cylinder with the same base surface area and a height as small as possible.
I guess the oblique cylinder has height h and it is divided into many (probably 10) cross-sections.
Option A: <span>πr2h
This is exactly the volume of the right cylinder, therefore, unless you are given a cross-section of height h (which would be too easy), this won't be the correct answer.
Option B: </span><span>4πr2h
This is 4 times the right cylinder. Again, here the height of the cross-section should</span> be 4h, but it doesn't sound like a possible data (too easy again).
Option C: <span>1 10 πr2h
Here comes a n issue with the notation: I think the right number you meant to write is (1/10)</span>·πr2h and not 110·<span>πr2h.
If I am right, this means that your oblique cylinder of height h is divided into 10 cross-sections, and therefore the volume of each of these cross-sections will be a tenth of the volume of the oblique cylinder, which means </span>1/10·<span>πr2h.
Option D: </span><span>1 2 πr2h
Here, we have the same notation issue as before. I think you meant (1/2)</span>·<span>πr2h.
Here, your oblique cylinder height h should be divided into only 2 cross-sections. Now, we said the cross-section's height should be the smallest as possible, so an oblique cylinder divided only into two pieces doesn't sound good.
Therefore, the most probable correct answer will be C) </span>(1/10)·<span>πr2h</span>
<span>Let be the length, and be the width.
If the length is 1.6 times the width, then
If the sum of the length and with (in feet) is 130, then
</span><span>Substituting in the equation above, the expression for , we get
--> --> -->
Ten, substituting the value found for in we find
-->
The two equations we set up at the start form a system of linear equations:
</span>
Answer:
1/14
Step-by-step explanation:
Odd numbers: 5, 7, 9
3/7 × 1/6
1/14
